尝试从Yahoo Weather XML中提取元素

Question

尝试从Yahoo XML Doc中的[yweather:astronomy]中提取sunrise元素的值。尝试了如下的各种组合:

echo $yweather->astronomy == 'sunrise';

从sunrise元素中提取值是正确的术语吗?在网上很难找到使用这个术语的帮助。

剩余的代码如我所愿

Yahoo XML Doc - snippet

<rss xmlns:yweather="http://xml.weather.yahoo.com/ns/rss/1.0" 
xmlns:geo="http://www.w3.org/2003/01/geo/wgs84_pos#" version="2.0">
  <channel>
    <title>Yahoo! Weather - New York, NY</title>
    <link>
      http://us.rd.yahoo.com/dailynews/rss/weather/New_York__NY/*http://weather.yahoo.com/forecast/USNY0996_f.html
    </link>
    <description>Yahoo! Weather for New York, NY</description>
    <language>en-us</language>
    <lastBuildDate>Mon, 12 Dec 2011 1:50 pm EST</lastBuildDate>
    <ttl>60</ttl>
    <yweather:location city="New York" region="NY" country="US"/>
    <yweather:units temperature="F" distance="mi" pressure="in" speed="mph"/>
    <yweather:wind chill="40" direction="0" speed="5"/>
    <yweather:atmosphere humidity="37" visibility="10" pressure="30.54" rising="2"/>
    <yweather:astronomy sunrise="7:09 am" sunset="4:26 pm"/>

rssweather.php

<?php
// Get XML data from source
$feed = file_get_contents("http://weather.yahooapis.com/forecastrss?p=USNY0996&u=f");
// Check to ensure the feed exists
if(!$feed){
die('Weather not found! Check feed URL');
}
$xml = new SimpleXmlElement($feed);
foreach ($xml->channel as $entry){
    echo "<strong>Description</strong> "; 
    echo $entry->description; 
    echo "<br /><strong>Collected on</strong> ";
    echo $entry->lastBuildDate;
    //Use that namespace
    $yweather = $entry->children("http://xml.weather.yahoo.com/ns/rss/1.0");
    echo "<br /><strong>Sunrise</strong> ";
    echo $yweather->astronomy == 'sunrise';
}
>?

Answer 1

我的最终解决方案

// Get and return sunrise time 
function get_sunrise_time(SimpleXMLElement $xml) {
    $weather['sunrise'] = $xml->channel->children('yweather', TRUE)->astronomy[1]->attributes()->sunrise;
    return $weather;
}