用于获取url IOS内容的编码

Question

我想获取我托管的url的内容。url的内容是

<p class="citation_style_APA">Blaine, J. D. (1992). <i>Buprenorphine: An alternative treatment for opioid dependence</i>. Rockville, MD: U.S. Dept. of Health and Human Services, Public Health Service, Alcohol, Drug Abuse, and Mental Health Administration, National Institute on Drug Abuse. </p>

下面是我在字符串中获取上述内容的代码。

NSString *s =[NSString stringWithFormat:@"%@",@"xyz.com"];
url = [NSURL URLWithString:s];
NSString *content = [NSString stringWithContentsOfURL:url encoding:NSASCIIStringEncoding error:nil];
NSLog(@"%@",content);

我快疯了，有人能告诉我哪里出了问题吗。

Answer 1

尝试一个完整的网址，如@"http://www.xyz.com/myfile.html".一旦你让它工作起来，你就会想改用异步技术。

Answer 2

您需要做两件事。

1. you should use a valid url
2. NSString *content=[[NSString string] initWithContentsOfURL:url encoding:NSASCIIStringEncoding error:Nil];

现在查看您的日志；这肯定行得通。

Answer 3

尝试这种方式

NSString *strUrl  = < YOUR URL >
NSURL    *url     = [NSURL URLWithString:[strUrl stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
NSError  *error   = nil;
NSString *content = [NSString stringWithContentsOfURL:url encoding:NSASCIIStringEncoding error:&error];
if(content==nil)
    NSLog(@"%@",error!=nil ? error.description : @"");
else
    NSLog(@"%@",content);