使用泛型 C# 反序列化动态 XML

Question

给定以下XML：

<RESPONSE version="10">
    <RESULTS MyAttribute="1" />
</RESPONSE>

我可以像这样反序列化它：

[XmlRoot("RESPONSE")]
public class Response
{
    [XmlElement(ElementName = "RESULTS")]
    public Results Results {get;set;}
}
public class Results
{
    [XmlAttribute(AttributeName = "MyAttribute")]
    public bool MyAttribute { get; set; }
}
var serializer = new XmlSerializer(typeof(Response));
var result = (Response)serializer.Deserialize(new StringReader(xml));

这有效并且很好。但是，问题是我还想反序列化以下XML，并且我不想复制Response类，我想使用通用方法。

<RESPONSE version="10">
    <SOCCER AnotherAttribute="1" />
</RESPONSE>

我尝试执行以下操作：

[XmlRoot("Response")]
public class Response<T>
{
    public T Data {get;set;}
}
public class SoccerRoot
{
    [XmlElement(ElementName = "SOCCER")]
    public class Soccer {get;set;}
}
public class Soccer
{
    [XmlAttribute(AttributeName = "AnotherAttribute")]
    public bool AnotherAttribute {get;set;}
}

var serializer = new XmlSerializer(typeof(Response<SoccerRoot>));
var result = (Response<SoccerRoot>)serializer.Deserialize(new StringReader(xml));

但这行不通，我也尝试继承 Response 类，但没有运气。我收到以下错误：<xmlns='' > was not expected.

我在这里的方式是否正确，还是在反序列化 XML 文件时无法使用通用方法？

Answer 1

对于Response<SoccerRoot>，预期的 xml 布局将是：

<RESPONSE>
    <Data>
        <SOCCER AnotherAttribute=...>

这与你所拥有的不匹配。无法仅使用属性自定义T Data的元素名称。

选项：

• 有多个根对象(SOCCER、RESULTS等各一个(：

  [XmlRoot("RESPONSE")]
  public class SoccerRoot {
      [XmlElement("SOCCER")]
      public Soccer Soccer {get;set;}
  }
  [XmlRoot("RESPONSE")]
  public class ResultsRoot {
      [XmlElement("RESULTS")]
      public Results Results {get;set;}
  }
  

• 有一个根对象，该对象具有多个一级子对象(一个用于SOCCER，一个用于RESULTS等 - 每种类型都是一种

  [XmlRoot("RESPONSE")]
  public class Response {
      [XmlElement("RESULTS")]
      public Results Results {get;set;}
      [XmlElement("SOCCER")]
      public Soccer Soccer {get;set;}
  }
  

• 使用泛型方法，但丢失中间对象，以便您Response<Soccer>(完全删除SoccerRoot(，并使用XmlAttributeOverrides自定义元素名称，确保缓存生成的XmlSerializer(否则它将以惊人的速度泄漏(

坦率地说，我会选择前两个选项中的任何一个，而不管第三个选项。

Answer 2

尝试创建一个包含对象 RESULTS 和 SOCCER 的公共类，然后基于数据，一个为 null，另一个将包含值。

class Program
{
    static void Main(string[] args)
    {
        //
        var xml = "<RESPONSE  version="1" ><SOCCER AnotherAttribute ="1" /></RESPONSE>";
        var serializer = new XmlSerializer(typeof(Response<int>));
        var result = (Response<int>)serializer.Deserialize(new StringReader(xml));
        xml = "<RESPONSE version="10"><RESULTS MyAttribute = "1" /></RESPONSE >";
        result = (Response<int>)serializer.Deserialize(new StringReader(xml));
        Console.ReadLine();
    }
}
[XmlRoot("RESPONSE")]
public class Response<T>
{
    [XmlAttribute(AttributeName = "version")]
    public T Version { get; set; }
    [XmlElement(ElementName = "SOCCER")]
    public SoccerRoot SoccerRoot { get; set; }
    [XmlElement(ElementName = "RESULTS")]
    public Results Results { get; set; }
}
public class SoccerRoot
{
    [XmlAttribute(AttributeName = "AnotherAttribute")]
    public int AnotherAttribute { get; set; }
}
public class Results
{
    [XmlAttribute(AttributeName = "MyAttribute")]
    public bool MyAttribute { get; set; }
}