字符串转换为 Array in Solidity

Question

在 Solidity 中，有没有办法使用分隔符将字符串文本转换为数组来识别字符串中的复合部分

例

mystring = "This-Is-A-Problem";

自

myArray = [This,Is,A,Problem];   // using hyphen as separator

Answer 1

更新的答案，适用于最新的编译器

import "github.com/Arachnid/solidity-stringutils/strings.sol";
contract Contract {                                                            
    using strings for *;                                                       
    function smt() public pure {                                               
        strings.slice memory s = "This-Is-A-Problem".toSlice();                
        strings.slice memory delim = "-".toSlice();                            
        string[] memory parts = new string[](s.count(delim));                  
        for (uint i = 0; i < parts.length; i++) {                              
           parts[i] = s.split(delim).toString();                               
        }                                                                      
    }                                                                          
}  

https://ethfiddle.com/TgY5JxLKvn

Answer 2

Crema 的答案几乎是正确的，但请注意，对于 n 个部分，我们有 n-1 个分隔符。修改他的代码给我们：

import "github.com/Arachnid/solidity-stringutils/strings.sol";
contract Contract {
   using strings for *;
   // ...
   function smt() {
    var s = ""This-Is-A-Problem"".toSlice();
    var delim = "-".toSlice();
    var parts = new string[](s.count(delim) + 1);
    for(uint i = 0; i < parts.length; i++) {
       parts[i] = s.split(delim).toString();
    }
   }
}

Answer 3

没有内置的方法/函数，但您可以使用solidity-stringutils。

import "github.com/Arachnid/solidity-stringutils/strings.sol";
contract Contract {
    using strings for *;
    // ...
    function smt() {
        var s = ""This-Is-A-Problem"".toSlice();
        var delim = "-".toSlice();
        var parts = new string[](s.count(delim));
        for(uint i = 0; i < parts.length; i++) {
           parts[i] = s.split(delim).toString();
        }
    }
}