将从方法类发出的信号连接到不同的类插槽自定义信号 PySide

Question

我想将从closeWidgetUI类方法发出的信号连接到addTool类方法中。但这似乎只适用于 PyQt4，而不适用于 PySide。每次我点击在self.close_btn.clicked.connect(self.closeWidgetUI(中创建的closeButton时，程序都会冻结并自行关闭。有什么好说的吗？

import PySide.QtCore as qc
import PySide.QtGui  as qg
class InterpolateIt(dc,qg.QDialog):
def __init__(self):
qg.QDialog.__init__(self)
""" MORE THINGS 
OVER THIS PART NOT IMPORTANT AT MOMENT"""
add_button.clicked.connect(self.addTool)
def addTool(self):
#NEED TO CONNECT closeWidgetUI EMITED SIGNAL HERE 
new_widget = InterpolateWidget()
self.clicked.connect(new_widget, qc.SIGNAL('CLOSE'), self.removeTool)
def removeTool(self,interpWidget):
self.interpolateLayout.removeWidget(interpWidget)
interpWidget.deleteLater()

# ------------------------------------------------------------------------------------------------------#        
class InterpolateWidget(qg.QFrame):
def __init__(self):
qg.QFrame.__init__(self)
""" MORE THINGS 
OVER THIS PART NOT IMPORTANT AT MOMENT"""
# HERE BUTTON EMIT SIGNAL AT CLICKED
self.close_btn.clicked.connect(self.closeWidgetUI)
# TRIGGER THIS FUNC
def closeWidgetUI(self):
self.emit(qc.SIGNAL('CLOSE'), self)

Answer 1

from functools import partial
def addTool(self):
#NEED TO CONNECT closeWidgetUI EMITED SIGNAL HERE 
new_widget = InterpolateWidget()
deleteTool = partial(self.removeTool,new_widget)
new_widget.close_btn.clicked.connect(deleteTool)

我就是这样做到的！多亏了我的大脑:)干杯