DJGPP使DOS成为"多目标模式"

Question

我在DOS下使用DJGPP make。

这是我的主要制作文件：

BIN_DIR = bin
OBJ_DIR = obj
DIRS_FOR_CREATION = $(BIN_DIR) $(OBJ_DIR)
SOURCE_DIRS = argparse logger transmission tests
EXECUTABLE_NAME = $(notdir $(shell pwd))
EXECUTABLE_FILE = $(BIN_DIR)/$(EXECUTABLE_NAME)
CC = cc
CFLAGS =
INCLUDES =
LFLAGS =
LIBS =
MAIN_SOURCE = main.c
MAIN_OBJ = $(OBJ_DIR)/main.o
all: directories submodules main $(EXECUTABLE_FILE)
@echo $(EXECUTABLE_NAME) was compiled
directories:
mkdir -p $(DIRS_FOR_CREATION)
submodules: 
$(MAKE) -C $(word 1, $(SOURCE_DIRS))
$(MAKE) -C $(word 2, $(SOURCE_DIRS))
$(MAKE) -C $(word 3, $(SOURCE_DIRS))
$(MAKE) -C $(word 4, $(SOURCE_DIRS))
main:
$(CC) $(CFLAGS) $(INCLUDES) -c $(MAIN_SOURCE) -o $(MAIN_OBJ)
$(EXECUTABLE_FILE): $(MAIN_SOURCE)
$(CC) $(CFLAGS) $(INCLUDES) -o $(EXECUTABLE_FILE) $(MAIN_OBJ) $(LFLAGS) $(LIBS)

这在 QNX 上非常有效，但在 DOSBox 中我收到以下错误：

makefile:19: *** multiple target patterns. Stop.

19行all: directories submodules main $(EXECUTABLE_FILE)。我应该怎么做才能解决这个问题？

Answer 1

您应该添加：

$(info EXECUTABLE_NAME = '$(EXECUTABLE_NAME)')
$(info EXECUTABLE_FILE = '$(EXECUTABLE_FILE)')

因此，您可以看到该变量包含的内容。 我怀疑它包含一个冒号(:(，这是特别的。