我在Django模型中有一个属性,我想通过TastyPie ModelResource公开它。
我的型号是
class UserProfile(models.Model):
_genderChoices = ((u"M", u"Male"), (u"F", u"Female"))
user = Models.OneToOneField(User, editable=False)
gender = models.CharField(max_length=2, choices = _genderChoices)
def _get_full_name(self):
return "%s %s" % (self.user.first_name, self.user.last_name)
fullName = property(_get_full_name)
我的模型资源是
class UserProfileResource(ModelResource):
class Meta:
queryset = models.UserProfile.objects.all()
authorization = DjangoAuthorization()
fields = ['gender', 'fullName']
然而,我目前从tastypie api中得到的只是:
{
gender: 'female',
resource_uri: "/api/v1/userprofile/55/"
}
我尝试过在ModelResource中使用fields属性,但这没有帮助。我很想了解这里发生了什么。
您应该能够将其定义为字段try:
class UserProfileResource(ModelResource):
fullname = fields.CharField(attribute='_get_full_name', readonly=True)
class Meta:
queryset = models.UserProfile.objects.all()
authorization = DjangoAuthorization()
fields = ['gender',]
编辑
您还必须在CharField
上包含:set readonly=True
,否则TastyPie将尝试在插入或更新时设置其值。
脱水的完整示例:
class UserResource(ModelResource):
fullname = fields.CharField(readonly=True)
class Meta:
queryset = auth_models.User.objects.all()
resource_name = 'user'
def dehydrate_fullname(self, bundle):
return u"{first_name} {last_name}".format(
first_name=bundle.obj.first_name, last_name=bundle.obj.last_name)