c-简单链表-无法访问节点

Question

我试图构建一个简单的链表，但我遇到了一个编译错误，告诉我我试图访问的链表节点没有包含我期望的字段。以下是我的链表方法：

typedef struct TinCan
    {
    int label;
    } TinCan;
typedef struct LinkedListNode
    {
    TinCan *data;
    struct LinkedListNode *next;
    } LinkedListNode;
typedef struct LinkedList
    {
    LinkedListNode *head;
    } LinkedList;
LinkedList* createList() /*creates empty linked list*/
    {
    LinkedList* myList;
    myList = (LinkedList*)malloc(sizeof(LinkedList));
    myList->head = NULL;
    }

我对一个结构进行malloc并将其发送到列表中，如下所示：

LinkedList* canQueue=createList();
TinCan* testCan = (TinCan*) malloc(sizeof(TinCan));
testProc->pid=69;
insertLast(canQueue, testCan);
void insertLast(LinkedList* list, ProcessActivity *newData)
    {
        int ii = 1;
    LinkedListNode* newNode = (LinkedListNode*)malloc(sizeof(LinkedListNode));
    newNode->data = newData;
    //check if queue empty
    if(list->head == NULL)
        {
        list->head = newNode;
        newNode->next=NULL;
        }
    else
        {
        LinkedListNode* current = list->head;
        while (current->next != NULL)
            {
            current = current->next;
            }
        current->next = newNode;
        printf("%d", ii);
        ii++;
        }
}

然后我尝试访问这样的节点：

testLinkedList(cpuQueue);
void testLinkedList(LinkedList* list)
    {
        int count = 1;
        LinkedListNode* current = list->head;
        while (current != NULL)
            {
            printf("%d: Label is is %d", count, current->data->label);

            current = current->next;
            count++;
            }
    }

最后一个方法出现编译错误："LinkedListNode"没有名为"label"的成员。我看不出哪里出了问题，有人能识别出代码的问题吗？

Answer 1

TinCan没有字段pid

也许：

testProc->label=69;

而不是

testProc->pid=69;

Answer 2

LinkedList* createList() /*creates empty linked list*/
{
  LinkedList* myList;
  myList = (LinkedList*)malloc(sizeof(LinkedList));
  myList->head = NULL;

-->return myList；

}