我有一个SPARQL端点使用Java代码的问题。
特别是,我有这个Java类:
public class example {
public static void main(String[] args) {
String value = "http://dbpedia.org/resource/Fred_Guy";
example exam = example();
QueryExecution qe = exam.query(value);
ResultSet results = ResultSetFactory.copyResults( qe.execSelect() );
}
public QueryExecution query(String stringa){
ParameterizedSparqlString qs = new ParameterizedSparqlString( "" +
"prefix dbpediaont: <http://dbpedia.org/ontology/>n" +
"prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>n" +
"n" +
"select ?resource where {n" +
"?mat rdf:type ?resourcen" +
"filter strstarts(str(?resource), dbpediaont:)n" +
"}" );
Resource risorsa = ResourceFactory.createResource(stringa);
qs.setParam( "mat", risorsa );
QueryExecution exec = QueryExecutionFactory.sparqlService( "http://dbpedia.org/sparql", qs.asQuery() );
ResultSet results = ResultSetFactory.copyResults( exec.execSelect() );
while ( results.hasNext() ) {
System.out.println( results.next().get( "resource" ));
}
// A simpler way of printing the results.
ResultSetFormatter.out( results );
return exec;
}
}
我想检索谓词为"RDF:type"的资源"http://dbpedia.org/resource/Fred_Guy"的对象。但是我有这个错误,我不明白:
Exception in thread "main" HttpException: 500
at com.hp.hpl.jena.sparql.engine.http.HttpQuery.execGet(HttpQuery.java:340)
at com.hp.hpl.jena.sparql.engine.http.HttpQuery.exec(HttpQuery.java:276)
at com.hp.hpl.jena.sparql.engine.http.QueryEngineHTTP.execSelect(QueryEngineHTTP.java:345)
at MyPackage.example.main(example.java:19)
为什么我得到这个错误?
我想在
上执行这个查询" http://dbpedia.org/sparql "
不写字符串,我得到这个错误:
Virtuoso 37000 Error SP031: SPARQL compiler: No one quad map pattern is suitable for GRAPH <http://dbpedia.org> { "http://dbpedia.org/resource/Fred_Guy" <http://www.w3.org/1999/02/22-rdf-syntax-ns#type> ?resource } triple at line 7
SPARQL query:
define sql:big-data-const 0
#output-format:text/html
define sql:signal-void-variables 1 define input:default-graph-uri <http://dbpedia.org> prefix dbpediaont: <http://dbpedia.org/ontology/>
prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
select ?resource where {
"http://dbpedia.org/resource/Fred_Guy" rdf:type ?resource
}
我在这里做错了什么?
我尝试在Virtuoso中编写以下代码:
prefix dbpediaont: <http://dbpedia.org/ontology/>
prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
select ?resource where {
dbpedia:Fred_Guy rdf:type ?resource
}
SPARQL结果我如何用耶拿代码写它?
这里有两个查询。在问题的最后,您使用了一个没有过滤器的查询,但这与代码中嵌入的查询不同。如果在DBpedia的端点上使用嵌入在代码中的查询,则会得到一条非常明确的错误消息:
Virtuoso 22023 Error SL001: The SPARQL 1.1 function STRSTARTS() needs a string value as 2d argument
SPARQL query:
define sql:big-data-const 0
#output-format:text/html
define sql:signal-void-variables 1 define input:default-graph-uri <http://dbpedia.org> prefix dbpediaont: <http://dbpedia.org/ontology/>
prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
select ?resource where {
?mat rdf:type ?resource
filter strstarts(str(?resource), dbpediaont:)
}
关键是
SPARQL 1.1函数STRSTARTS()需要一个字符串值作为2d参数
你需要用str()
写dbpediaont:
,因为它是一个IRI,而不是字符串:
filter strstarts(str(?resource), str(dbpediaont:))