我想喜欢兴趣1,不喜欢兴趣0
案例R.id.floatingActionButton:
if() {floatingActionButton.setImageDrawable(getResources().getDrawable(R.drawable.hearts));
addToInterested(postId, 1);
}else {
floatingActionButton.setImageDrawable(getResources().getDrawable(R.drawable.ic_action_fav));
addToInterested(postId, 0);
}
break;
在方法内private void addToInterested(String postId, int interest) {
try {
PostLikeTask postLikeTask = new PostLikeTask(this, responseListener);
JSONObject params = new JSONObject();
params.put("userId", authKey);
params.put("postId", postId);
params.put("interest", interest);
postLikeTask.likePost(params);
} catch (Exception e) {
e.printStackTrace();
}
}
ResponseListener responseListener = new ResponseListener() {
@Override
public void onError(String errorMessage) {
Toast.makeText(getApplicationContext(), errorMessage.toString(), Toast.LENGTH_LONG).show();
}
@Override
public void onSuccess(String message) {
Toast.makeText(getApplicationContext(), message.toString(), Toast.LENGTH_LONG).show();
}
};
}
您可以使用全局curInterest
来保存当前感兴趣的状态。
或者检查FloatingButton的状态:
Drawable myDrawable = floatingButton.getDrawable();
if(floatingButton.getDrawable()==getResources().getDrawable(R.drawable. hearts)){
//Liked
}
但是,我看到floatingButton
你改变背景,不要关心addToInterested
状态成功或错误,当你的请求太快或有错误时,它可以使错误状态