我必须打开/res/raw/
文件夹中的一个文件,但android似乎无法识别路径。
这是我的代码:
public static void openRec()
{
//this is the wav file that I have to analyze
File file = new File("/res/raw/chirp.wav");
try {
FileInputStream in = new FileInputStream(file);
chirp = new byte[(int) file.length()];
in.read(chirp);
Log.d("xxx", "" + chirp.length);
in.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
编辑:我有另一个方法openRec,其中,路径作为参数传递:
public static void openRec(String path) {
File file = new File(path);
try {
FileInputStream in = new FileInputStream(file);
recording = new byte[(int) file.length()];
in.read(recording);
Log.d("xxx", "" + recording.length);
in.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
我想要一个做同样事情的方法,但使用了/res/raw中的ffile。我该怎么做?
以这种方式使用
public static void openRec()
{
//this is the wav file that I have to analyze
try {
InputStream in = getResources().openRawResource(R.raw.chirp);
chirp = new byte[(int) file.length()];
in.read(chirp);
Log.d("xxx", "" + chirp.length);
in.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}