我正在创建内容类型传记的XML feed,该XML具有实体参考术语字段。我正在加载节点,加载段落字段,然后使用TERM ::加载术语对象在段落字段中加载术语对象,该段落字段是by Term ID编号。但是,当我尝试从术语本身中获取字段时,我不能在我使用的行 -> name-> value的行上扔"试图获取非对象的属性"而不这样做。这些领域成功地被抓住并渲染了,这些错误只是随之而来的。尝试使用 -> getName((方法完全打破了提要。
private function xmlOutput($input) {
$node = Node::load($input);
$educationArray = $node->get('field_group_education');
$educationOutput = [];
foreach ($educationArray as $key => $value) {
$educationGroupID = $node->get('field_group_education')[$key]->target_id;
$educationGroup = Paragraph::load($educationGroupID);
$honors = $educationGroup->get('field_academic_honors')->value;
$degreeID = $educationGroup->get('field_degrees')->target_id;
$degree = Term::load($degreeID)->name->value;
$educationID = $educationGroup->get('field_education')->target_id;
$schoolName = Term::load($educationID)->name->value;
$yearGraduated = $educationGroup->get('field_year_graduated')->value;
$educationRender = '<professionalEducation>
<order>' . $key . '</order>
<school whereField="Name" whereValue="' . $schoolName . '" autoCreate="true"/>
<educationType whereField="Name" whereValue="' . $degree . '" autoCreate="true"/>
<yearGraduated>' . $yearGraduated . '</yearGraduated>
<degree whereField="Name" whereValue="' . $degree . '" autoCreate="true"/> .
<honors>' . $honors . '</honors>
</professionalEducation>';
array_push($educationOutput, $educationRender);
}
$compiled = [
'<education>',
implode($educationOutput),
'</education>',
];
return implode('', $compiled);
}
这将成功
<education>
<professionalEducation>
<order>0</order>
<school whereField="Name" whereValue="education term 1"
autoCreate="true"/>
<educationType whereField="Name" whereValue="AA" autoCreate="true"/>
<yearGraduated>1990</yearGraduated>
<degree whereField="Name" whereValue="AA" autoCreate="true"/>
<honors>Honors 1</honors>
</professionalEducation>
<professionalEducation>
<order>1</order>
<school whereField="Name" whereValue="education term 2" autoCreate="true"/>
<educationType whereField="Name" whereValue="AB" autoCreate="true"/>
<yearGraduated>2000</yearGraduated>
<degree whereField="Name" whereValue="AB" autoCreate="true"/>
<honors>honors 2</honors>
</professionalEducation>
</education>
,但我会得到具有 -> name-> value行的"试图获得非对象的属性"的PHP错误我尝试使用 -> getName((方法,但这立即引发了500个错误。使用ISSET检查是否有一个值对使GetName((工作也不有用。
$degree = '';
if(isset(Term::load($degreeID)->name->value)) {
$degree = $degreeObject->name->value;
}
有效,但错误仍然存在
$degree = '';
if(isset(Term::load($degreeID)->getName())) {
$degree = $degreeObject->getName();
}
扔500个错误,但也摆脱了错误
检查target_id isset()
。修改您的代码如下
$educationGroup = $value->entity;
$honors = isset($educationGroup->field_academic_honors->target_id) ? $educationGroup->field_academic_honors->value : '';
$degree = isset($educationGroup->field_degrees->target_id) ? $educationGroup->field_degrees->entity->name->value : '';
$schoolName = isset($educationGroup->field_education->target_id) ? $educationGroup->field_education->entity->name->value : '';
$yearGraduated = isset($educationGroup->field_year_graduated->target_id) ? $educationGroup->field_year_graduated->value : '';
无需加载段 and term 每次都可以使用entity
参考获得它们。