def skip_elements(elements) :
new_list = []
for i in elements :
if i % 2 == 0 :
new_list= new_list.append(i)
i+=1
else :
i+=1
return new_list
print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) # Should be ['a', 'c', 'e', 'g']
print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach'])) # Should be ['Orange', 'Strawberry', 'Peach']
print(skip_elements([])) # Should be []
if i % 2 == 0 :
new_list= new_list.append(i)
i+=1
else :
i+=1
^ extra space - you might want to use tabs instead of spaces when it comes to python - or any language for that matter
new_list = new_list.append(i)
.append()将返回None。替换为：
new_list.append(i)
最后，返回一个包含所有奇数元素的列表需要付出很多努力。你可以简单地做(感谢@chepner(：
def skip_elements(elements):
return elements[::2]