首先,我是非常新的进度4GL,仍然试图得到我的头周围嵌套为每个块的工作原理。我有以下两个表,我从中获取信息,ivc_header和ivc_mchgs:
ivc_header
invoice_nbr | sold_to_cust_nbr | sold_to_cust_seq | invoice_amt
1000051 | 70 | 0 | $1,000
1000049 | 70 | 1 | $1,500
1000010 | 310 | 0 | $2,000
1000011 | 310 | 1 | $2,500
ivc_mchgs
invoice_nbr | line_nbr | misc_seq_nbr | extension
1000051 | 1 | 1 | $300
1000051 | 1 | 2 | $200
1000051 | 2 | 1 | $100
1000049 | 1 | 1 | $400
1000049 | 1 | 2 | $100
1000049 | 2 | 1 | $150
1000010 | 1 | 1 | $50
1000010 | 1 | 2 | $50
1000010 | 2 | 1 | $100
1000011 | 1 | 1 | $75
1000011 | 1 | 2 | $80
1000011 | 2 | 1 | $90
仅供参考,ivc_header的主键是invoice_nbr, ivc_mchgs的主键是由invoice_nbr, line_nbr和misc_seq_nbr组成的复合键。外键为invoice_nbr。
关于数据的注意事项,ivc_mchgs中的信息是发票line_nbr中的杂项费用。
我想要得到的是sold_to_cust_nbr + sold_to_cust seq的总发票和扩展。在做了一些研究之后,我决定将总数放在变量中,而不是使用Progress内置的ACCUMULATE函数。
下面是我的代码:
DEFINE VARIABLE cCustNum AS CHARACTER NO-UNDO.
DEFINE VARIABLE dInvoiceSubTotal AS DECIMAL NO-UNDO.
DEFINE VARIABLE dSurchargeTotal AS DECIMAL NO-UNDO.
FOR EACH ivc_header
NO-LOCK
WHERE (ivc_header.sold_to_cust_nbr = "000070")
OR (ivc_header.sold_to_cust_nbr = "000310")
BREAK BY ivc_header.sold_to_cust_nbr:
IF FIRST-OF(ivc_header.sold_to_cust_nbr) THEN
ASSIGN dInvoiceSubTotal = 0.
ASSIGN dInvoiceSUbTotal = dInvoiceSUbTotal + ivc_header.invoice_amt.
IF LAST-OF(ivc_header.sold_to_cust_nbr) THEN
DISPLAY ivc_header.sold_to_cust_nbr + ivc_header.sold_to_cust_seq FORMAT "x(9)" LABEL "CustNum"
dInvoiceSUbTotal LABEL "SubTotal".
FOR EACH ivc_mchgs WHERE ivc_header.invoice_nbr = ivc_mchgs.invoice_nbr
NO-LOCK
BREAK BY ivc_mchgs.invoice_nbr:
IF FIRST-OF(ivc_mchgs.invoice_nbr) THEN
ASSIGN dSurchargeTotal = 0.
ASSIGN dSurchargeTotal = dSurchargeTotal + ivc_mchgs.extension.
IF LAST-OF (ivc_mchgs.invoice_nbr) THEN
DISPLAY
dSurchargeTotal LABEL "Surcharge".
END.
END.
此代码将通过sold_to_cust_nbr + sold_to_custrongeq为我提供总invoice_amt,并通过invoice_nbr对扩展进行汇总。我不知道如何做的是获得sold_to_cust_nbr + sold_to_custrongeq的总扩展。
任何帮助都是感激的。
谢谢
我想你可能没有意识到你可以指定多个BY子句。
现在你可能想要像这样编写内部的FOR EACH:
FOR EACH ivc_mchgs NO-LOCK WHERE ivc_header.invoice_nbr = ivc_mchgs.invoice_nbr
BREAK BY ivc_mchgs.invoice_nbr
BY ivc_mchgs.sold_to_cust_nbr
BY ivc_mchgs.sold_to_cust_seq:
IF FIRST-OF(ivc_mchgs.invoice_nbr) THEN
ASSIGN dSurchargeTotal = 0.
IF FIRST-OF(ivc_mchgs.sold_to_cust_nbr ) THEN ...
等。
假设您需要发票和汇总表的交换总额,那么您可以这样做:
DEFINE VARIABLE cCustNum AS CHARACTER NO-UNDO.
DEFINE VARIABLE dInvoiceSubTotal AS DECIMAL NO-UNDO.
DEFINE VARIABLE dSurchargeTotal AS DECIMAL NO-UNDO.
DEFINE VARIABLE dSurchargeSubTl AS DECIMAL NO-UNDO.
FOR EACH ivc_header
NO-LOCK
WHERE (ivc_header.sold_to_cust_nbr = "000070")
OR (ivc_header.sold_to_cust_nbr = "000310")
BREAK BY ivc_header.sold_to_cust_nbr:
IF FIRST-OF(ivc_header.sold_to_cust_nbr) THEN
ASSIGN dInvoiceSubTotal = 0
dSurchargeSubTl = 0.
ASSIGN dInvoiceSUbTotal = dInvoiceSUbTotal + ivc_header.invoice_amt.
IF LAST-OF(ivc_header.sold_to_cust_nbr) THEN
DISPLAY ivc_header.sold_to_cust_nbr + ivc_header.sold_to_cust_seq FORMAT "x(9)" LABEL "CustNum"
dInvoiceSUbTotal LABEL "SubTotal"
dSurchargeSubTL LABEL "Srchg SubTl".
FOR EACH ivc_mchgs WHERE ivc_header.invoice_nbr = ivc_mchgs.invoice_nbr
NO-LOCK
BREAK BY ivc_mchgs.invoice_nbr:
IF FIRST-OF(ivc_mchgs.invoice_nbr) THEN
ASSIGN dSurchargeTotal = 0.
ASSIGN dSurchargeTotal = dSurchargeTotal + ivc_mchgs.extension.
IF LAST-OF (ivc_mchgs.invoice_nbr) THEN DO:
DISPLAY dSurchargeTotal LABEL "Surcharge".
ASSIGN dSurchargeSubTl = dSurchargeSubTl + dSurchargeTotal.
END.
END.
END.
优雅的方式是使用左外连接组合两个查询,并使用ACCUMULATE函数,但这应该可以工作。