如何在ListView中计算具有相同id的子节点

Question

我有一个ListView，它有多个Linearlayout。(1) LinearLayout-> FrameLayout->使用-> ImageView(2) LinearLayout-> FrameLayout->使用-> ImageView

如何计数ImageView的个数?它们都有相同的id

Answer 1

您可以使用自定义匹配器-公共最终类CustomMatchers {

public static Matcher<View> childAtPosition(
        final Matcher<View> parentMatcher, final int position) {
    return new TypeSafeMatcher<View>() {
        @Override
        public void describeTo(Description description) {
            description.appendText("Child at position " + position + " in parent ");
            parentMatcher.describeTo(description);
        }
        @Override
        public boolean matchesSafely(View view) {
            ViewParent parent = view.getParent();
            return parent instanceof ViewGroup && parentMatcher.matches(parent)
                    && view.equals(((ViewGroup) parent).getChildAt(position));
        }
    };
}

}

在您的测试用例中使用它-

ViewInteraction textView9 = onView(
                allOf(withText("ViewName"),
                        CustomMatchers.childAtPosition(
                          CustomMatchers.childAtPosition(withId(R.id.view)id), 1), 0), isDisplayed()))