Java 基转换程序给定值、其基数和新基数

Question

我正在尝试弄清楚如何将特定基中的任何值转换为不同基数中的相应表示。在.dat文件的每一行中，您将获得一个值、其基数以及该值需要转换为的基数。

.dat文件中的 3 行示例，其中一行中的第一个数字是值，后跟它所在的基数，然后是需要转换为的基数：

10

10 2

AB 16 10

345 6 4

我相信我已经弄清楚了，除了如何解释 16 和 18 等基数中的字母值。请帮忙：

public static void main( String args[] ) throws IOException
    {
        Scanner file = new Scanner(new File("baseConversion.dat"));
        //Keep looping while you can still read lines from the file
        while (file.hasNextLine())
        {
            //Read a line from the file -- read it as a string
            String line = file.nextLine();
            int firstSpace = line.indexOf(" ");
            int lastSpace = line.lastIndexOf(' ', line.length());
            String oldBase = line.substring(firstSpace + 1, lastSpace); 

            // Get the new base from the string
            int newBase = Integer.parseInt(line.substring(lastSpace + 1));

            //  Convert from the Old base to base 10
            int numberInBase10 = convertToTen(line.substring(0, firstSpace), Integer.parseInt(oldBase));
            System.out.println("Converted " + line.substring(0, firstSpace) + " from base " + oldBase + " to " +
            numberInBase10 + " in base 10n");
            public static String convert(int numberInBase10, int base)
            {
            int quotient = numberInBase10 / newBase;
            int remainder = numberInBase10 % newBase;
            if(quotient == 0)
            {
                return Integer.toString(remainder);      
            }
            else
            {
                return convert(quotient, newBase) + Integer.toString(remainder);
            }
        }
        // DO THIS Print out results

        }
        file.close();
    }

    static int convertToTen(String num, int base)
    {
    int leng = num.length();
    int base10 = 0;
    int remainder = 0;
    int add = 0;

        for(int i = leng-1; i >=0; i--)
        {
            int intValueForC = 0;
            remainder = 0;
            char c = num.charAt(leng-i-1);
            if(!Character.isDigit(c))
            {
                intValueForC = c - 55;
            }
            else
            {
                intValueForC = c - 48;
            }
            add +=(intValueForC * Math.pow(base, i));
        }
        return add;
    }
}

Answer 1

你把这大大复杂化了

（除非这是家庭作业并且你不允许使用库函数）。

String hex = "ABCDEF";
int decimal = Integer.parseInt(hex, 16);
String binary = Integer.toString(decimal, 2);