无法使用 C# 运行两行三列字符串数组

Question

我的代码在这里。但我有两个错误。数组初始化程序只能在变量或字段初始化程序中使用。请尝试使用新表达式。

using System;
public class twoDimArray
{
 public static void Main(string[] args)
{
   String[] city=new String[] { {"NewYork","Muscat","London"} ,{"Cairo","Beijing","CapeTown"}  };
    for (int i=0; i<2; i++)
    {for (int j=0; j<3; j++)
   {
      System.Console.Write(city[i][j]+"t");
  }
      System.Console.Write("n");
  }
 }
}

Answer 1

将您的声明更改为

String[,] city = new String[,] { 
                     { "NewYork", "Muscat", "London" }, 
                     { "Cairo", "Beijing", "CapeTown" } };

而不是硬编码的上限，这将是更好的

for (int i = 0; i < city.GetLength(0); i++)
{
    for (int j = 0; j < city.GetLength(1); j++)
    {
        Console.Write(city[i, j] + "t");
    }
    Console.WriteLine();
}

Answer 2

试试这个

String[,] city=new String[,] { {"NewYork","Muscat","London"} ,{"Cairo","Beijing","CapeTown"}  };

Answer 3

试试这个：

String[] city=new String[] { "NewYork","Muscat","London","Cairo","Beijing","CapeTown"  };

而不是：

String[] city=new String[] { {"NewYork","Muscat","London"} ,{"Cairo","Beijing","CapeTown"}  };

第二个是错误的，因为您正在初始化一个数组中的另外两个数组。

var city=new List<String[]> {new [] {"NewYork","Muscat","London"} , new []{"Cairo","Beijing","CapeTown"}};

这将创建字符串数组列表，或者此代码将创建二维数组：

String[,] city=new String[,] { {"NewYork","Muscat","London"} ,{"Cairo","Beijing","CapeTown"}  };

Answer 4

String[] city=new String[]是一维数组。。。。

use String[,] city=new String[,]()

Answer 5

好吧，这取决于你想要实现的目标。如果是二维数组，您应该使用：

String[,] city = new String[,]{ { "NewYork", "Muscat", "London" }, { "Cairo", "Beijing", "CapeTown" } };

并调用，例如，它是这样的：

System.Console.Write(city[0, 1]);

Answer 6

尽管使用

   string[,] = new string...

可以很好地工作，如果你需要序列化它，我不推荐它。我宁愿使用字符串列表。

 List<object> firstLevel = new List<object>();
 List<string> secondLevel = new List<string>("first", "second", "third");
 firstLevel.Add(secondLevel);
 secondLevel = ("first", "second", "third");
 firstLevel.Add(secondLevel);