表:产品
create table Product
(
productID int,
productName varchar(20),
productsalesdate DATETIME,
producttype varchar(20)
);
插入:
insert into product values(1,'PenDrive','2010-01-01','Electronic');
insert into product values(1,'Computer','2016-01-01','Electronic');
insert into product values(1,'Laptop','2011-02-02','Electronic');
insert into product values(2,'textbook','2014-02-02','books');
insert into product values(2,'notebook','2016-01-01','books');
insert into product values(3,'Car','2016-01-01','Vehicle');
insert into product values(3,'Bike','2016-01-07','Vehicle');
第一次尝试:在这种情况下,我得到了错误的产品类型的总和
SELECT productID, FirstSale,LastSale, [Electronic],[books],[Vehicle]
FROM
(
SELECT
productID,
MIN(ProductSalesdate) as FirstSale,
MAX(ProductSalesdate) as LastSale,
productType
FROM
Product
Group by productID,productType
) a
PIVOT
(
COUNT(productType)
FOR productType IN ( [Electronic],[books],[Vehicle] )
) AS pvt;
第二次尝试:在这次尝试中,我已经解决了求和问题,但对于大量记录,执行查询需要更多时间。
SELECT productID,FirstSale,LastSale ,[Electronic],[books],[Vehicle]
FROM
(
SELECT a.ProductID, a.FirstSale, a.LastSale, b.ProductType
FROM Product b
inner join
(
SELECT
productID,
MIN(ProductSalesdate) as FirstSale,
MAX(ProductSalesdate) as LastSale
FROM
Product
Group by productID
) as a
ON a.ProductID = b.ProductID
) ab
PIVOT
(
COUNT(productType)
FOR productType IN ( [Electronic],[books],[Vehicle] )
) AS pvt;
注意:第二个查询工作正常,但问题在于性能,因为我加入了两个相同的表,因为要在透视查询中获得productType的计数。
问题:如何优化我第二次尝试的第二个查询?
下面使用一个临时表来存储派生表ab
。我的猜测是,它将改进第二个查询的执行计划。
SELECT a.ProductID, a.FirstSale, a.LastSale, b.ProductType
INTO #ab
FROM Product b
inner join
(
SELECT
productID,
MIN(ProductSalesdate) as FirstSale,
MAX(ProductSalesdate) as LastSale
FROM
Product
Group by productID
) as a
ON a.ProductID = b.ProductID;
SELECT productID,FirstSale,LastSale ,[Electronic],[books],[Vehicle]
FROM #ab AS ab
PIVOT
(
COUNT(productType)
FOR productType IN ( [Electronic],[books],[Vehicle] )
) AS pvt;
DROP TABLE #ab;
编辑:只是为了体育,我写了以下脚本,在#产品中有15k行。整个脚本在大约1秒内执行完毕。我仍然不明白你的查询怎么花了5.5分钟。如下:
SET NOCOUNT ON;
CREATE TABLE #product (
product_id INT,
product_name VARCHAR(20),
product_sales_date DATE,
product_type VARCHAR(20)
);
DECLARE @cnt INT=0;
WHILE @cnt<15000
BEGIN
INSERT INTO #product(
product_id,
product_name,
product_sales_date,
product_type
)
SELECT
product_id=ROUND(20*RAND(),0),
product_name=LEFT(NEWID(),20),
product_sales_date=DATEADD(DAY,ROUND((-10+20*RAND()), 0),GETDATE()),
product_type=
CASE ROUND(2*RAND(),0)
WHEN 0 THEN 'Electronic'
WHEN 1 THEN 'books'
ELSE 'Vehicle'
END;
SET @cnt=@cnt+1;
END
SELECT a.product_id, a.first_sale, a.last_sale, b.product_type
INTO #ab
FROM #product b
inner join
(
SELECT
product_id,
MIN(product_sales_date) as first_sale,
MAX(product_sales_date) as last_sale
FROM
#product
GROUP BY
product_id
) as a
ON a.product_id= b.product_id;
SELECT product_id,first_sale,last_sale,[Electronic],[books],[Vehicle]
FROM #ab AS ab
PIVOT
(
COUNT(product_type)
FOR product_type IN ( [Electronic],[books],[Vehicle] )
) AS pvt;
DROP TABLE #ab;
DROP TABLE #product;
看起来你正试图做这样的事情。。不确定为什么需要额外的联接或临时表。。
SELECT * FROM
(
SELECT productID,
productType,
MIN(ProductSalesdate) as FirstSale,
MAX(ProductSalesdate) as LastSale,
COUNT(productType) AS ProductCount
FROM Product
GROUP BY productID,productType
) t
PIVOT
(
SUM(ProductCount)
FOR productType IN ([Electronic],[books],[Vehicle])
) p
您将获得0计数的NULLS,但您可以很容易地将这些值合并为0