Pyqt5 qthread+信号不工作+gui冻结



我正在尝试用imapLib制作一个邮箱检查器,它在没有gui的情况下可以很好地使用python、队列和多线程。

但当我尝试放置gui时,我做的每一个动作都会让gui冻结直到完成。

我尝试了各种文档中的许多内容(添加qthread、signal、cursorr等)和教程,但都不适用。

有人能帮我理解如何在运行函数时设置或附加文本到QtextEdit吗?因为它只有在完成后才能工作。

这是我的代码:

class Checker(QtCore.QThread):
signal = QtCore.pyqtSignal(object)
def __init__(self, lignesmailtocheck):
QtCore.QThread.__init__(self)
self.lignesmailtocheck = lignesmailtocheck
def run(self):
lignemailtocheck = self.lignesmailtocheck.strip()                        
maillo, passo = lignemailtocheck.split(":",1)
debmail, finmail = maillo.split("@",1)
setimap =["oultook.com:imap-mail.outlook.com", "gmail.com:imap.gmail.com"]
for lignesimaptocheck in sorted(setimap):
ligneimaptocheck = lignesimaptocheck.strip()
fai, imap = ligneimaptocheck.split(":",1)                                
if finmail == fai:
passo0 = passo.rstrip()
try :
mail = imaplib.IMAP4_SSL(imap)
mail.login(maillo, passo)
mailboxok = open("MailBoxOk.txt", "a+", encoding='utf-8', errors='ignore')
mailboxok.write(maillo+":"+passo+"n")
mailboxok.close()
totaly = maillo+":"+passo0+":"+imap                                
print(maillo+":"+passo+"n")
self.send_text.emit(totaly)
time.sleep(1)
except imaplib.IMAP4.error:                          
print ("LOGIN FAILED!!! ")
class Ui_Form(object):
def setupUi(self, Form):
Form.setObjectName("Form")
Form.resize(400, 300)
self.pushButton = QtWidgets.QPushButton(Form)
self.pushButton.setGeometry(QtCore.QRect(150, 210, 75, 23))
self.pushButton.setObjectName("pushButton")
self.pushButton.clicked.connect(self.gogogo)
self.openliste = QtWidgets.QToolButton(Form)
self.openliste.setGeometry(QtCore.QRect(40, 110, 71, 21))
self.openliste.setObjectName("openliste")
self.textEdit = QtWidgets.QTextEdit(Form)
self.textEdit.setGeometry(QtCore.QRect(170, 50, 201, 121))
self.textEdit.setObjectName("textEdit")
self.progressBar = QtWidgets.QProgressBar(Form)
self.progressBar.setGeometry(QtCore.QRect(10, 260, 381, 23))
self.progressBar.setValue(0)
self.progressBar.setObjectName("progressBar")
self.retranslateUi(Form)
QtCore.QMetaObject.connectSlotsByName(Form)
def retranslateUi(self, Form):
_translate = QtCore.QCoreApplication.translate
Form.setWindowTitle(_translate("Form", "Form"))
self.pushButton.setText(_translate("Form", "PushButton"))
self.openliste.setText(_translate("Form", "..."))
def gogogo(self):
mailtocheck = open('File/toCheck.txt', 'r', encoding='utf-8', errors='ignore').readlines()        
setmailtocheck = set(mailtocheck)
for lignesmailtocheck in sorted(setmailtocheck):
checker = Checker(lignesmailtocheck)
thread = QThread()
checker.moveToThread(thread)
# connections after move so cross-thread:
thread.started.connect(checker.run)
checker.signal.connect(self.checkedok)
thread.start()
def checkedok(self, data):
print(data)
self.textEdit.append(data)
if __name__ == "__main__":
app = QtWidgets.QApplication(sys.argv)
Form = QtWidgets.QWidget()
ui = Ui_Form()
ui.setupUi(Form)
Form.show()
sys.exit(app.exec_())

由于在PyQt中使用QThread经常会有问题,与您的问题类似,因此这里有一个示例演示如何在PyQt中正确使用线程。我希望它能作为类似问题的goto答案有用,所以我花了比平时更多的时间准备这个。

该示例创建了许多在非主线程中执行并通过Qt的异步信号与主线程(即GUI)通信的工作对象。

import time
import sys
from PyQt5.QtCore import QObject, QThread, pyqtSignal, pyqtSlot
from PyQt5.QtWidgets import QApplication, QPushButton, QTextEdit, QVBoxLayout, QWidget

def trap_exc_during_debug(*args):
# when app raises uncaught exception, print info
print(args)

# install exception hook: without this, uncaught exception would cause application to exit
sys.excepthook = trap_exc_during_debug

class Worker(QObject):
"""
Must derive from QObject in order to emit signals, connect slots to other signals, and operate in a QThread.
"""
sig_step = pyqtSignal(int, str)  # worker id, step description: emitted every step through work() loop
sig_done = pyqtSignal(int)  # worker id: emitted at end of work()
sig_msg = pyqtSignal(str)  # message to be shown to user
def __init__(self, id: int):
super().__init__()
self.__id = id
self.__abort = False
@pyqtSlot()
def work(self):
"""
Pretend this worker method does work that takes a long time. During this time, the thread's
event loop is blocked, except if the application's processEvents() is called: this gives every
thread (incl. main) a chance to process events, which in this sample means processing signals
received from GUI (such as abort).
"""
thread_name = QThread.currentThread().objectName()
thread_id = int(QThread.currentThreadId())  # cast to int() is necessary
self.sig_msg.emit('Running worker #{} from thread "{}" (#{})'.format(self.__id, thread_name, thread_id))
for step in range(100):
time.sleep(0.1)
self.sig_step.emit(self.__id, 'step ' + str(step))
# check if we need to abort the loop; need to process events to receive signals;
app.processEvents()  # this could cause change to self.__abort
if self.__abort:
# note that "step" value will not necessarily be same for every thread
self.sig_msg.emit('Worker #{} aborting work at step {}'.format(self.__id, step))
break
self.sig_done.emit(self.__id)
def abort(self):
self.sig_msg.emit('Worker #{} notified to abort'.format(self.__id))
self.__abort = True

class MyWidget(QWidget):
NUM_THREADS = 5
# sig_start = pyqtSignal()  # needed only due to PyCharm debugger bug (!)
sig_abort_workers = pyqtSignal()
def __init__(self):
super().__init__()
self.setWindowTitle("Thread Example")
form_layout = QVBoxLayout()
self.setLayout(form_layout)
self.resize(400, 800)
self.button_start_threads = QPushButton()
self.button_start_threads.clicked.connect(self.start_threads)
self.button_start_threads.setText("Start {} threads".format(self.NUM_THREADS))
form_layout.addWidget(self.button_start_threads)
self.button_stop_threads = QPushButton()
self.button_stop_threads.clicked.connect(self.abort_workers)
self.button_stop_threads.setText("Stop threads")
self.button_stop_threads.setDisabled(True)
form_layout.addWidget(self.button_stop_threads)
self.log = QTextEdit()
form_layout.addWidget(self.log)
self.progress = QTextEdit()
form_layout.addWidget(self.progress)
QThread.currentThread().setObjectName('main')  # threads can be named, useful for log output
self.__workers_done = None
self.__threads = None
def start_threads(self):
self.log.append('starting {} threads'.format(self.NUM_THREADS))
self.button_start_threads.setDisabled(True)
self.button_stop_threads.setEnabled(True)
self.__workers_done = 0
self.__threads = []
for idx in range(self.NUM_THREADS):
worker = Worker(idx)
thread = QThread()
thread.setObjectName('thread_' + str(idx))
self.__threads.append((thread, worker))  # need to store worker too otherwise will be gc'd
worker.moveToThread(thread)
# get progress messages from worker:
worker.sig_step.connect(self.on_worker_step)
worker.sig_done.connect(self.on_worker_done)
worker.sig_msg.connect(self.log.append)
# control worker:
self.sig_abort_workers.connect(worker.abort)
# get read to start worker:
# self.sig_start.connect(worker.work)  # needed due to PyCharm debugger bug (!); comment out next line
thread.started.connect(worker.work)
thread.start()  # this will emit 'started' and start thread's event loop
# self.sig_start.emit()  # needed due to PyCharm debugger bug (!)
@pyqtSlot(int, str)
def on_worker_step(self, worker_id: int, data: str):
self.log.append('Worker #{}: {}'.format(worker_id, data))
self.progress.append('{}: {}'.format(worker_id, data))
@pyqtSlot(int)
def on_worker_done(self, worker_id):
self.log.append('worker #{} done'.format(worker_id))
self.progress.append('-- Worker {} DONE'.format(worker_id))
self.__workers_done += 1
if self.__workers_done == self.NUM_THREADS:
self.log.append('No more workers active')
self.button_start_threads.setEnabled(True)
self.button_stop_threads.setDisabled(True)
# self.__threads = None
@pyqtSlot()
def abort_workers(self):
self.sig_abort_workers.emit()
self.log.append('Asking each worker to abort')
for thread, worker in self.__threads:  # note nice unpacking by Python, avoids indexing
thread.quit()  # this will quit **as soon as thread event loop unblocks**
thread.wait()  # <- so you need to wait for it to *actually* quit
# even though threads have exited, there may still be messages on the main thread's
# queue (messages that threads emitted before the abort):
self.log.append('All threads exited')

if __name__ == "__main__":
app = QApplication([])
form = MyWidget()
form.show()
sys.exit(app.exec_())

理解PyQt中的多线程编程所需的主要概念如下:

  • Qt线程有自己的事件循环(特定于每个线程)。主线程,也就是GUI线程,也是一个QThread,其事件循环由该线程管理
  • 线程之间的信号通过接收线程的事件循环进行传输(异步)。因此GUI或任何线程的响应能力=处理事件的能力。例如,如果线程在函数循环中很忙,它就无法处理事件,因此在函数返回之前,它不会响应GUI的信号
  • 如果线程中的工作对象(方法)可能必须根据GUI的信号改变其操作过程(例如,中断循环或等待),则它必须在QApplication实例上调用processEvents()。这将允许QThread处理事件,从而调用插槽以响应来自GUI的异步信号。注意,QApplication.instance().processEvents()似乎在每个线程上都调用processEvents(),如果不希望这样做,那么QThread.currentThread().processEvents()是一个有效的替代方案
  • QThread.quit()的调用不会立即退出其事件循环:它必须等待当前执行的槽(如果有的话)返回。因此,一旦线程被告知退出,你就必须等待()。因此,中止工作线程通常需要(通过自定义信号)向它发出信号,让它停止它正在做的任何事情:这需要GUI对象上的自定义信号,该信号与工作槽的连接,并且工作方法必须调用线程的processEvents(),以允许发出的信号在工作时到达槽

我无法测试,因为setimap在我的系统上不可用。我将CheckerThread重命名为Checker,因为它不再是线程(它只是"生活"在线程中):

class Checker(QtCore.QObject):

然后将gogogo(self)中循环的内容替换为:

for lignesmailtocheck in sorted(setmailtocheck):
checker = Checker(lignesmailtocheck)
thread = QThread()
checker.moveToThread(thread)
# connections after move so cross-thread:
thread.started.connect(checker.run)
checker.signal.connect(self.checkedok)
thread.start()
self.threads.append(thread)

pyqtSlot装饰插槽几乎总是一个好主意,因此runcheckedok都应该这样装饰。

SO对Qt线程的回答非常方便,可以提醒您注意细节(但请注意,它使用旧式连接——您必须将C++connect( sender, SIGNAL(sig), receiver, SLOT(slot));转换为PyQt5sender.sig.connect(receiver.slot))。

很抱歉回答晚了,但这是一种可以解决类似问题的技术。

问题很明显。GUI冻结是因为它的线程必须执行另一项工作。下面给出了一个抽象的(从PyQt点)解决方案:

  1. 创建一个从线程继承的类。线程将成为工作者
  2. 向构造函数传递一个队列(queue.queue)作为通信手段
  3. 您可以从GUI线程启动工作线程,并使用队列传递消息
  4. 要使GUI线程读取消息,请创建一个具有您选择的间隔的QTimer,并注册一个回调函数。在回调函数中读取队列

示例代码:

class Worker(threading.Thread):
def __init__(self, queue):
super().init()
self.queue = queue
def run(self):
# Your code that uses self.queue.put(object)
class Gui:
def __init__(self):
self.timer = Qtimer()
self.timer.setInterval(milliseconds)
self.timer.timeout.connect(self.read_data)

def start_worker(self):
self.queue = queue.Queue()
thr = Worker(self.queue)
thr.start()

def read_data(self):
data = self.queue.get()

self.timer.timeout.connect注册回调函数。

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