HashMap.containesKey由于某种原因无法工作

Question

我想知道为什么逻辑if (!map.containsKey("Africa"))既不去if块（XX）也不去else块（YY）

public class HashMapWithListTest {
public static void main (String args[]) {
    HashMap<String,List<String>> map=new HashMap<String,List<String>>();
    //to put data firs time
    String country="USA";
    //create list for cities
    List<String> cityList=new ArrayList<String>();
    //then fill list
    cityList.add("New York");
    cityList.add("Los Angeles ");
    cityList.add("Chicago");
    //lets put this data to map
    map.put(country, cityList);
    //same thind with other data
    country="Pakistan";
    cityList=new ArrayList<String>();
    cityList.add("Lahore");
    cityList.add("Karachi");
    map.put(country, cityList);
    country="Malaysia";
    cityList=new ArrayList<String>();
    cityList.add("Kuala Lumpur");
    cityList.add("Johor Baru");
    map.put(country, cityList);
    country="Indonesia";
    cityList=new ArrayList<String>();
    cityList.add("Jakarta");
    cityList.add("Bandung");
    map.put(country, cityList);
    //now lets check what is in map
    System.out.println(map);
    //to add city in USA
    //you need to get List of cities and add new one 
    map.get("USA").add("Washington");
    //to get all values from USA
    System.out.println("city in USA:");
    List<String> tmp=map.get("USA");
    for (String city:tmp)
        System.out.println(city);
    System.out.println("x------------------x");
    map.remove("USA");
    System.out.println(map);
    System.out.println("x------------------x");
    map.get("Indonesia").add("Lembang");
    System.out.println(map.get("Indonesia"));
    System.out.println("x------------------x");
    country="Indonesia";
    cityList=new ArrayList<String>();
    cityList.add("Semarang");
    cityList.add("Bali");
    map.putIfAbsent(country, cityList);
    if (!map.containsKey("Africa")) {
        System.out.println(map.get("XX"));
    } else {
        System.out.println(map.get("YY"));
    }
}

}

Answer 1

map.containsKey("Africa")在代码中返回false（因为HashMap中没有这样的键），然后map.get("XX")生成null值（HashMap中没有与"XX"键相关的值），该值由System.out.println打印。

代码是正确的，可能存在语义问题

Answer 2

检查密钥存在的最佳方法：

Myobject value = map.get(key);
if (value != null) {
...
} else {
if (map.containsKey(key)) {
   // key exists but it's null
} else {
   // No such key
}
}

因为这是HashMap.contationsKey的工作方式：

@Override
public boolean containsKey(Object key) {
Entry<K, V> m = getEntry(key);
return m != null;
}

Answer 3

它将进入if循环。。如果要进行检查，请使用System.out.println("XX"); 重新铺设System.out.println(map.get("XX"));