如何在WP-Config文件中使用条件语句使WP-CLI工作

Question

我正在使用WP-CLI进行测试，以更新我的域名prod，dev，staging，test和update站点。

我的wp-config文件中有有条件的语句，然后我收到以下错误：

PHP Notice:  Undefined index: HTTP_HOST in phar:///usr/local/bin/wp/php/WP_CLI/Runner.php(1070) : eval()'d code on line 22
PHP Notice:  Undefined index: HTTP_HOST in phar:///usr/local/bin/wp/php/WP_CLI/Runner.php(1070) : eval()'d code on line 24
PHP Notice:  Undefined index: HTTP_HOST in phar:///usr/local/bin/wp/php/WP_CLI/Runner.php(1070) : eval()'d code on line 26
PHP Notice:  Undefined index: HTTP_HOST in phar:///usr/local/bin/wp/php/WP_CLI/Runner.php(1070) : eval()'d code on line 28
PHP Notice:  Undefined variable: db_name in phar:///usr/local/bin/wp/php/WP_CLI/Runner.php(1070) : eval()'d code on line 34
Error: Can’t select database. We were able to connect to the database server (which means your username and password is okay) but not able to select the `` database.

这是我对wp-config.php文件进行编码的方式！！！

if ($_SERVER["HTTP_HOST"] === 'example.com') {
  $db_name = 'example';
}else if ($_SERVER["HTTP_HOST"] === 'dev.example.com') {
  $db_name = 'example_dev';
}else if ($_SERVER["HTTP_HOST"] === 'staging.example.com'){
  $db_name = 'example_staging';
}else if ($_SERVER["HTTP_HOST"] === 'update.example.com') {
  $db_name = 'example_update';
}
define('DB_NAME', $db_name);

有什么办法可以让WP-CLI使用此文件？

Answer 1

$_SERVER["HTTP_HOST"]

从命令行使用PHP时，

不存在。最好的选择是在命令行中使用文件时指定一个情况，例如：

if (php_sapi_name() == "cli") {
    //set db_name when in cli
} else {
    //set db_name as per host
    if ($_SERVER["HTTP_HOST"] === 'example.com') {
      $db_name = 'example';
    }else if ($_SERVER["HTTP_HOST"] === 'dev.example.com') {
      $db_name = 'example_dev';
    }else if ($_SERVER["HTTP_HOST"] === 'staging.example.com'){
      $db_name = 'example_staging';
    }else if ($_SERVER["HTTP_HOST"] === 'update.example.com') {
      $db_name = 'example_update';
    }
}

我不太确定您想要$ db_name在WP-CLI时，我已经将其设置在第一组括号中。