Caused by: java.io.FileNotFoundException: Could not open Ser

我正在尝试通过使用spring hibernatetemplate将我的hibernate示例移植到spring，但我正在获得以下错误:java.io.FileNotFoundException:无法打开ServletContext资源[/applicationContext.xml]。请建议我运行我的项目。我在公司是新人

my web.xml file

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" 
    xmlns="http://java.sun.com/xml/ns/javaee" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
    http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
  <servlet-name>spring</servlet-name>
  <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
  <load-on-startup>1</load-on-startup>
 </servlet>

 <listener>
  <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
 </listener>

    <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>applicationContext.xml</param-value>
  </context-param>

</web-app>

我中

<?xml version="1.0" encoding="UTF-8"?>
<beans
    xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:p="http://www.springframework.org/schema/p"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">
<bean id="dataSource"
    class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
    <property name="driverClassName" value="com.mysql.jdbc.Driver"></property>
    <property name="url" value="jdbc:mysql://my server/emp_app"></property>
    <property name="username" value="root"></property>
    <property name="password" value="root"></property>
</bean>
<bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
    <property name="dataSource"> <ref bean="dataSource" /> </property>
    <property name="hibernateProperties">
        <props>
            <prop key="hibernate.dialect">
                org.hibernate.dialect.MySQLDialect
            </prop>
        </props>
    </property>
</bean>

    <bean id="d" class="login.HrDao">
    <property name="sessionFactory" ref="mysessionFactory"></property>
    </bean>
</beans>

my HrDAO.java file ->

package login;
import org.hibernate.SessionFactory;
import org.springframework.orm.hibernate3.HibernateTemplate;
public class HrDao {
    HibernateTemplate template;
    public void setSessionFactory(SessionFactory factory) {
        template = new HibernateTemplate(factory);
    }
    public void saveStudent(HrModel e) {
        template.save(e);
    }
}

MY HrMain.java File ->

package login;
import org.springframework.beans.factory.BeanFactory;
import org.springframework.beans.factory.xml.XmlBeanFactory;
import org.springframework.core.io.ClassPathResource;
import org.springframework.core.io.Resource;
public class HrMain {
    public static void main(String[] args) {
        Resource resource = new ClassPathResource("applicationContext.xml");
        BeanFactory factory = new XmlBeanFactory(resource);
        HrDao dao = (HrDao) factory.getBean("d");
    HrModel student = new HrModel();
        student.setEmployee_Name("Akash");
        student.setPassword("jaisiaram");
        dao.saveStudent(student);
    }
}

最后我的视图页->

<html>
<head>
<title></title>
</head>
<body>
<form action="HrMain" method="post">
<input type="text" name="Employee_Name"/>
<input type="text" name="password">
<input type="submit">
</form>
</body>
</html>

您的applicationContext.xml在哪里?您可以将web.xml中的applicationContext.xml称为:

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>

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