我正在尝试使用 java 中的do-while
循环打印斐波那契数列,但无法理解这一点。 需要介于 0 和 100 之间。
我有以下代码:
int prevPrevVal = 0;
int prevVal = 1;
int currVal;
System.out.println(prevPrevVal);
System.out.println(prevVal);
do
{
currVal = prevVal + prevPrevVal;
System.out.println(currVal);
prevPrevVal = prevVal;
prevVal = currVal;
} while (prevVal <= 100);
这是一个简化的程序,通过在 while 循环中提供条件限制来找出斐波那契级数。希望你们能对此有所了解....!!
int a=0;
int b=0;
int temp=1;
do {
a=b;
b=temp;
temp=a+b;
System.out.println(temp);
}while(temp<100);
设法使用两个变量来完成此操作,并且没有打印超出范围的数字。对不起,如果它很糟糕,这是我编程的第一天:)
int x = 0;
int y = 1;
do
{
System.out.println(x);
y = x + y;
if (y < 100)
{
System.out.println(y);
}
x = x + y;
} while (x < 100);
这应该是你的解决方案
public static void main(String[] args) {
int prevVal = 1;
int prevPrevVal = 0;
int n = 0;
do{
int currVal = prevVal + prevPrevVal;
prevPrevVal = prevVal;
prevVal = currVal;
System.out.print(currVal+" ");
n++;
}while(n<5);//n is the number of terms
}
你去 :
int prevVal = 1;
int prevPrevVal = 0;
do{
int currVal = prevVal + prevPrevVal;
//currVal is your Fibonacc seq.
prevPrevVal = prevVal;
prevVal = currVal;
}
while(yourCondition);
使用文档中do-while
循环的基本结构:
do {
statement(s)
} while (expression);
您希望在"语句"部分中通过每次迭代递增(并可能输出(结果。使用do-while
循环的基本斐波那契数列如下所示:
int prevVal = 1;
int prevPrevVal = 0;
int currVal;
do {
// Add the two numbers
currVal = prevVal + prevPrevVal;
// "Bump" up prevPrevVal to prevVal, and prevVal to currVal
prevPrevVal = prevVal;
prevVal = currVal;
// Output to the screen
System.out.println(currval + "n");
} while(expression);
由于您希望斐波那契的项最多为 100,只需将while (prevVal <= 100);
更改为 while (prevVal+prevPrevVal <= 100);
这将打印多达 89。