我试图从文件创建文件路径列表,但我似乎无法绕过文件路径中的空格。
# Show current series list
PS3="Type a number or 'q' to quit: "
# Create a list of files to display
Current_list=`cat Current_series_list.txt`
select fileName in $Current_list; do
if [ -n "$fileName" ]; then
Selected_series=${fileName}
fi
break
done
Current_series列表中的文件路径是:/Volumes/Lara's Hard Drive/LARA HARD DRIVE/SERIES/The Big Bang Theory 3/The.Big.Bang.Theory S03E11.avi
和
/卷/劳拉的硬盘/劳拉硬盘/系列/NAKITAS03E11.avi
所以我希望它们在我的列表中分别是 1 和 2,但我得到以下结果。
1) /Volumes/Lara's 6) Big
2) Hard 7) Bang
3) Drive/LARA 8) Theory
4) HARD 9) 3/The.Big.Bang.Theory
5) DRIVE/Series/The 10) S03E11.avi
Type a number or 'q' to quit:
你需要稍微欺骗一下:
# Show current series list
PS3="Type a number or 'q' to quit: "
# Create a list of files to display
Current_list=$(tr 'n' ',' < Current_series_list.txt)
IFS=, read -a list <<< "$Current_list"
select fileName in "${list[@]}"; do
if [ -n "$fileName" ]; then
Selected_series="${fileName}"
fi
break
done
echo "you selected $fileName"
执行:
$ ./a
1) /Volumes/Lara's Hard Drive/LARA HARD DRIVE/Series/The Big Bang Theory3/The.Big.Bang.Theory S03E11.avi
2) /Volumes/Lara's Hard Drive/LARA HARD DRIVE/Series/nakitaS03E11.avi
Type a number or 'q' to quit: 2
you selected /Volumes/Lara's Hard Drive/LARA HARD DRIVE/Series/nakitaS03E11.avi
关键是您必须将文件转换为数组。
这部分将其转换为"string one", "string two"
格式:
$ tr 'n' ',' < Current_series_list.txt
/Volumes/Lara's Hard Drive/LARA HARD DRIVE/Series/The Big Bang Theory 3/The.Big.Bang.Theory S03E11.avi,/Volumes/Lara's Hard Drive/LARA HARD DRIVE/Series/nakitaS03E11.avi,
虽然这个基于上一步中设置的逗号分隔符在变量list
中创建一个数组:
IFS=, read -a list <<< "$Current_list"
您可以尝试将每行Current_series_list.txt
分别读取到数组元素中,并从扩展的数组"${Current_array[@]}"
中进行选择:
# Show current series list
PS3="Type a number or 'q' to quit: "
# Create an array of files to display
Current_array=()
while read line; do Current_array+=("$line"); done < Current_series_list.txt
select fileName in "${Current_array[@]}"; do
if [ -n "$fileName" ]; then
Selected_series=${fileName}
fi
break
done