垂直打印字符串 - Python3.2

Question

我正在编写一个脚本，该脚本将作为用户输入的字符串，并垂直打印，如下所示：

input = "John walked to the store"
output = J w t t s
         o a o h t
         h l   e o
         n k     r
           e     e
           d

我已经编写了大部分代码，如下所示：

import sys
def verticalPrint(astring):
    wordList = astring.split(" ")
    wordAmount = len(wordList)
    maxLen = 0
    for i in range (wordAmount):
        length = len(wordList[i])
        if length >= maxLen:
            maxLen = length
    ### makes all words the same length to avoid range errors ###
    for i in range (wordAmount):
        if len(wordList[i]) < maxLen:
            wordList[i] = wordList[i] + (" ")*(maxLen-len(wordList[i]))
    for i in range (wordAmount):
        for j in range (maxLen):
            print(wordList[i][j])
def main():
    astring = input("Enter a string:" + 'n')
    verticalPrint(astring)
main()

我无法弄清楚如何正确输出。我知道这是 for 循环的问题。它的输出是：

input = "John walked"
output = J
         o
         h
         n
         w
         a
         l
         k
         e
         d

有什么建议吗？（另外，我希望打印命令只使用一次。

Answer 1

使用 itertools.zip_longest ：

>>> from itertools import zip_longest
>>> text = "John walked to the store"
for x in zip_longest(*text.split(), fillvalue=' '):
    print (' '.join(x))
...     
J w t t s
o a o h t
h l   e o
n k     r
  e     e
  d      

Answer 2

非常感谢您的帮助！这绝对奏效了！

发布此内容后不久，我最终与我的一个朋友交谈，我将 for 循环修改为以下内容：

newline = ""
    for i in range (maxLen):
        for j in range (wordAmount):
            newline = newline + wordList[j][i]
        print (newline)
        newline = ""

效果也很好。

Answer 3

a = input()
for x in range (0,len(a)):
    print(a[x])