基于另一个字段的验证

Question

我是这个Symfony框架的新手，在实现过程中遇到了死胡同。只有当输入了用户的current password时，我才需要验证new password和confirm password字段。

我尽力通过这些链接来理解这个概念，

• http://shout.setfive.com/2013/06/27/symfony2-forms-without-an-entity-and-with-a-conditional-validator/
• 基于Symfony 2中的字段A或字段B验证表单字段A
• http://tomislavsantek.iz.hr/2011/03/using-symfony-postvalidator/

但事实证明，要么使用的类被弃用，要么需要一个实体。

两个领域的实现如下，

//if this field is filled
$builder->add('currentPassword', 'password', array('label'=>'Current Password',                                            
                                      'required'=>false,                                          
                                      'attr'=>array('class'=>'form-control'),                                           
                                      'error_bubbling' => true,
                                      'trim' => true,
                                      'mapped' => false,
                                      'label_attr'=>array('class'=>'col-sm-4 control-label')));
//These repeated fields must be filled or must be set as required
$builder->add( 'password', 'repeated', array( 'type' => 'password',                                          
                                      'required' => false,        
                                      'invalid_message' => ErrorMessages::PASSWORDS_DO_NOT_MATCH,
                                      'options' => array('attr' => array('class' => 'password-field form-control')),                                                                                   
                                      'first_options'  => array('label' => false,  
                                                                'error_bubbling' => true,
                                                                'label_attr'=>array('class'=>'col-sm-4 control-label')),
                                      'second_options' => array('label' => false,                                                                    
                                                                'label_attr'=>array('class'=>'col-sm-4 control-label')))); 

我在控制器中使用了一组if条件来实现验证，但如果能学习到在这种情况下执行验证的正确方法，那就太好了。：）

谢谢

编辑

用户entity

    <?php
    namespace ProjBundleAccountsBundleEntity;
    use SymfonyComponentValidatorConstraints as Assert;
    use SymfonyComponentSecurityCoreUserUserInterface;
    use ProjBundleAccountsBundleCustomErrorMessages;

    class User implements UserInterface, Serializable {    
      /**
       * @AssertEmail(message=ErrorMessages::EMAIL_ADDRESS_INVALID)
       * @AssertNotBlank(message=ErrorMessages::EMAIL_ADDRESS_EMPTY)
       */
      private $email;
      /**     
       * @AssertNotBlank(message=ErrorMessages::PASSWORD_EMPTY, groups={"full"})
       */
      private $password;
      private $oldPassword;
      private $id;
      private $userId;
      private $name;
      private $username;

      public function __construct() {
      } 
      function setEmail ($email) {
        $this->email = $email;
        $this->username = $email;
      }
      function getEmail () {
        return $this->email;
      }
      function setPassword ($password) {
        $this->password = $password;
      }
      function getPassword () {
        return $this->password;
      }
      function setOldPassword ($oldPassword) {
        $this->oldPassword = $oldPassword;
      }
      function getOldPassword () {
        return $this->oldPassword;
      }
      function setId ($id) {
        $this->id = $id;
      }
      function getId () {
        return $this->id;
      }
      function setUserId ($userId) {
        $this->userId = $userId;
      }
      function getUserId () {
        return $this->userId;
      }
      function setName (PersonName $name) {
        $this->name = $name;
      }
      function getName () {
        return $this->name;
      }
      public function eraseCredentials() {
      }
      public function getRoles() {
        return array('ROLE_USER');
      }
      public function getSalt() {
      }
      public function getUsername() {
        return $this->username;
      }
    }

Answer 1

如下修改您的类

use SymfonyComponentValidatorConstraints as Assert;
use SymfonyComponentValidatorExecutionContext;
/**
 *
 * @AssertCallback(methods={"passwordVerify"})
 */
class User implements UserInterface, Serializable {
  //all your old code here
  public function passwordVerify(ExecutionContext $context)
  {
    //your controls about password fields here
    //in case of failure you can add that snippet of code
    $context->addViolationAtPath($propertyPath,'your message here', array(), null);
  }
}

当然，你必须能够访问passwordVerify函数中的所有信息，最快的方法是在实体中创建字段verifyPassword，这样当你将表单与实体绑定时，所有数据都会在那里。

当您使用isValid()表单的方法