我正在尝试使用JAXB实现将类对象转换为XML,反之亦然。我通过观察一个教程来实现这一点。
我的XML看起来像这个
<Alphabet>
<a>Apple</a>
<b>Ball</b>
<c>Cat</c>
<d>Dog</d>
<e>Elephant</e>
<f>Fox</f>
</Alphabet>
我写了以下课程
import java.util.LinkedHashMap;
import java.util.Map.Entry;
import java.util.Set;
public class Alph {
@XmlElement
private LinkedHashMap<String, String> cLinkedHashMap = new
LinkedHashMap<String, String>();
protected void put(String theKey, String theValue) {
cLinkedHashMap.put(theKey, theValue);
}
protected String get(String theKey) {
return (String) cLinkedHashMap.get(theKey);
}
protected Set<Entry<String,String>> getCEntrySet() {
return cLinkedHashMap.entrySet();
}
protected LinkedHashMap<String, String> getCLinkedHashMap() {
return cLinkedHashMap;
}
public String toCXML() throws XMLHandlingException {
return null;
}
}
@XmlRootElement
public class Alphabet extends Alph {
public static Alphabet getInstance(String theAlphabetXML) throws
XMLHandlingException {
return XMLUtils.parseAlphabetXML(theAlphabetXML);
}
public String toCXML() throws XMLHandlingException {
return XMLUtils.getAlphabetXML(this);
}
}
我创建了以下XMLUtil方法来编组和取消编组
public static String getAlphabetXML(Alph theAlphabet) throws XMLHandlingException {
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
Writer writer = null;
try {
writer = new OutputStreamWriter(byteArrayOutputStream, "UTF-8");
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
try {
writer.write("<?xml version="1.0" encoding="UTF-8" ?>" );
} catch (IOException e) {
e.printStackTrace();
}
try {
JAXBContext JContext = JAXBContext.newInstance(Alphabet.class);
Marshaller JMarshaller = JContext.createMarshaller();
JMarshaller.marshal(theAlphabet, writer);
} catch (Throwable e) {
e.printStackTrace();
}
String theAlphabetXML = byteArrayOutputStream.toString();
return theAlphabetXML;
}
public static Alphabet parseAlphabetXML(String theAlphabetXML) throws
XMLHandlingException {
if(null == theAlphabetXML) {
return null;
}
try {
InputStream IPStream = new ByteArrayInputStream(theALphabetXML.getBytes());
JAXBContext JContext = JAXBContext.newInstance(Alphabet.class);
Unmarshaller JUnmarshaller = JContext.createUnmarshaller();
Alphabet alphabet = (Alphabet) JUnmarshaller.unmarshal(IPStream);
return alphabet;
} catch(Throwable t) {
t.printStackTrace();
}
}
我的问题是,当我试图整理或取消整理时,我会遇到以下错误"javax.xml.bind.UnmarshalException:意外元素(a:",local:"Alphabet")。预期元素为<{}Alphabet>"
我错过什么了吗?感谢您的帮助。
感谢
更新
我紧随其后http://blog.bdoughan.com/2013/06/moxys-xmlvariablenode-using-maps-key-as.html并更新了我的代码如下
请求和响应XML
<AlphabetReq>
<a>Apple</a>
<b>Ball</b>
<c>Cat</c>
<d>Dog</d>
<e>Elephant</e>
<f>Fox</f>
</AlphabetReq>
<AlphabetResp>
<a>Apple</a>
<b>Ball</b>
<c>Cat</c>
<d>Dog</d>
<e>Elephant</e>
<f>Fox</f>
</AlphabetResp>
AlphabetReq和AlphabetResp类
import java.util.LinkedHashMap;
import java.util.Map.Entry;
import java.util.Set;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;
import org.eclipse.persistence.oxm.annotations.XmlPath;
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Alph {
@XmlPath(".")
@XmlJavaTypeAdapter(AlphAdapter.class)
private LinkedHashMap<String, String> cLinkedHashMap = new
LinkedHashMap<String, String>();
@XmlPath(".")
@XmlJavaTypeAdapter(AlphAdapter.class)
private LinkedHashMap<String, String> gLinkedHashMap = new
LinkedHashMap<String, String>();
protected void put(String theKey, String theValue) {
cLinkedHashMap.put(theKey, theValue);
gLinkedHashMap.put(theKey, theValue);
}
protected String get(String theKey) {
return (String) cLinkedHashMap.get(theKey);
}
protected Set<Entry<String,String>> getCEntrySet() {
return cLinkedHashMap.entrySet();
}
protected Set<Entry<String,String>> getGEntrySet() {
return gLinkedHashMap.entrySet();
}
protected LinkedHashMap<String, String> getCLinkedHashMap() {
return cLinkedHashMap;
}
protected LinkedHashMap<String, String> getGLinkedHashMap() {
return gLinkedHashMap;
}
public String toCXML() throws XMLHandlingException {
return null;
}
public String toGXML() throws XMLHandlingException {
return null;
}
}
@XmlRootElement(name="AlphReq")
@XmlDiscriminatorValue("AlphabetReq")
@XmlAccessorType(XmlAccessType.FIELD)
public class AlphabetReq extends Alph {
public static AlphabetReq getInstance(String theAlphabetReqXML) throws
XMLHandlingException {
return XMLUtils.parseAlphabetReqXML(theAlphabetReqXML);
}
public String toCXML() throws XMLHandlingException {
return XMLUtils.getAlphabetReqXML(this);
}
}
@XmlRootElement(name="AlphResp")
@XmlDiscriminatorValue("AlphabetResp")
@XmlAccessorType(XmlAccessType.FIELD)
public class AlphabetResp extends Alph {
public static AlphabetResp getInstance(String theAlphabetRespXML) throws
XMLHandlingException {
return XMLUtils.parseAlphabetRespXML(theAlphabetRespXML);
}
public String toCXML() throws XMLHandlingException {
return XMLUtils.getAlphabetRespXML(this);
}
}
我创建了以下XMLUtil方法来编组和取消编组
public static String getAlphabetReqXML(Alph theAlphabet) throws XMLHandlingException {
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
Writer writer = null;
try {
writer = new OutputStreamWriter(byteArrayOutputStream, "UTF-8");
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
try {
writer.write("<?xml version="1.0" encoding="UTF-8" ?>" );
} catch (IOException e) {
e.printStackTrace();
}
try {
JAXBContext JContext = JAXBContext.newInstance(AlphabetReq.class);
Marshaller JMarshaller = JContext.createMarshaller();
JMarshaller.marshal(theAlphabet, writer);
} catch (Throwable e) {
e.printStackTrace();
}
String theAlphabetReqXML = byteArrayOutputStream.toString();
return theAlphabetReqXML;
}
public static AlphabetReq parseAlphabetReqXML(String theAlphabetReqXML) throws
XMLHandlingException {
if(null == theAlphabetReqXML) {
return null;
}
try {
InputStream IPStream = new ByteArrayInputStream(theAlphabetReqXML.getBytes());
JAXBContext JContext = JAXBContext.newInstance(AlphabetReq.class);
Unmarshaller JUnmarshaller = JContext.createUnmarshaller();
AlphabetReq alphabetreq = (AlphabetReq) JUnmarshaller.unmarshal(IPStream);
return alphabetreq;
} catch(Throwable t) {
t.printStackTrace();
}
}
public static String getAlphabetRespXML(Alph theAlphabet) throws XMLHandlingException {
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
Writer writer = null;
try {
writer = new OutputStreamWriter(byteArrayOutputStream, "UTF-8");
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
try {
writer.write("<?xml version="1.0" encoding="UTF-8" ?>" );
} catch (IOException e) {
e.printStackTrace();
}
try {
JAXBContext JContext = JAXBContext.newInstance(AlphabetResp.class);
Marshaller JMarshaller = JContext.createMarshaller();
JMarshaller.marshal(theAlphabet, writer);
} catch (Throwable e) {
e.printStackTrace();
}
String theAlphabetRespXML = byteArrayOutputStream.toString();
return theAlphabetRespXML;
}
public static AlphabetResp parseAlphabetReqXML(String theAlphabetRespXML) throws
XMLHandlingException {
if(null == theAlphabetRespXML) {
return null;
}
try {
InputStream IPStream = new ByteArrayInputStream(theAlphabetRespXML.getBytes());
JAXBContext JContext = JAXBContext.newInstance(AlphabetResp.class);
Unmarshaller JUnmarshaller = JContext.createUnmarshaller();
AlphabetResp alphabetresp = (AlphabetResp) JUnmarshaller.unmarshal(IPStream);
return alphabetresp;
} catch(Throwable t) {
t.printStackTrace();
}
}
并引入了适配器类
import java.util.*;
import java.util.Map.Entry;
import javax.xml.bind.annotation.*;
import javax.xml.bind.annotation.adapters.XmlAdapter;
import org.eclipse.persistence.oxm.annotations.XmlVariableNode;
public class AlphAdapter extends XmlAdapter<AlphAdapter.AdaptedMap, LinkedHashMap<String, String>>{
public static class AdaptedMap {
@XmlVariableNode("key")
List<AdaptedEntry> entries = new ArrayList<AdaptedEntry>();
}
public static class AdaptedEntry {
@XmlTransient
public String key;
@XmlValue
public String value;
}
@Override
public AdaptedMap marshal(LinkedHashMap<String, String> map) throws Exception {
AdaptedMap adaptedMap = new AdaptedMap();
for(Entry<String, String> entry : map.entrySet()) {
AdaptedEntry adaptedEntry = new AdaptedEntry();
adaptedEntry.key = entry.getKey();
adaptedEntry.value = entry.getValue();
adaptedMap.entries.add(adaptedEntry);
}
return adaptedMap;
}
@Override
public LinkedHashMap<String, String> unmarshal(AdaptedMap adaptedMap) throws Exception {
List<AdaptedEntry> adaptedEntries = adaptedMap.entries;
LinkedHashMap<String, String> map = new LinkedHashMap<String, String>(adaptedEntries.size());
for(AdaptedEntry adaptedEntry : adaptedMap.entries) {
map.put(adaptedEntry.key, adaptedEntry.value);
}
return map;
}
}
当我运行这个时,我不会在自适应映射中获得任何值。它有键,但值为null例如:
- 键:A,值:null
- 键:B,值:null
- 键:C,值:null
- 键:D,值:null
- 键:E,值:null
- 键:F,值:null
感谢您的帮助。
感谢
您可以实现以下简单的XML创建(您已经给出):
@XmlRootElement
public class Alphabet {
private String a;
private String b;
private String c;
private String d;
private String e;
private String f;
public Alphabet() {
}
public Alphabet(String a, String b, String c, String d, String e, String f) {
super();
this.a = a;
this.b = b;
this.c = c;
this.d = d;
this.e = e;
this.f = f;
}
public String getA() {
return a;
}
public void setA(String a) {
this.a = a;
}
public String getB() {
return b;
}
public void setB(String b) {
this.b = b;
}
public String getC() {
return c;
}
public void setC(String c) {
this.c = c;
}
public String getD() {
return d;
}
public void setD(String d) {
this.d = d;
}
public String getE() {
return e;
}
public void setE(String e) {
this.e = e;
}
public String getF() {
return f;
}
public void setF(String f) {
this.f = f;
}
}
这个类用于创建xml文件:
public class AlphabetToXML {
public static void main(String[] args) {
Alphabet alpha = new Alphabet("Apple", "Ball", "Cat", "Dog",
"Elephant", "Fox");
try {
String filePath = "PATH_TO_SAVE_YOUR_FILE";
File file = new File(filePath);
JAXBContext jaxbContext = JAXBContext.newInstance(Alphabet.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
// output pretty printed
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(alpha, file);
jaxbMarshaller.marshal(alpha, System.out);
} catch (JAXBException e) {
e.printStackTrace();
}
}
}
这是将XML读取回Java对象:
public class XMLToAplhabet {
public static void main(String[] args) {
try {
String filePath = "XML_FILE_PATH";
File file = new File(filePath);
JAXBContext jaxbContext = JAXBContext.newInstance(Alphabet.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
Alphabet aplha = (Alphabet) jaxbUnmarshaller.unmarshal(file);
System.out.println(aplha);
} catch (JAXBException e) {
e.printStackTrace();
}
}
}
我看不到使用LinkedHashMap来创建这样一个简单的XML。
http://java.dzone.com/articles/jaxb-and-javautilmap可能会有所帮助。包含执行同一任务的不同方法。