我是C 的初学者,并且正在将C代码(TWAMP RFC5357)移植到一个新项目(IPSLA RFC 6812),我遇到了此问题:
当我尝试使用函数 send 时,我会看到错误"错误c2664:'send':无法将参数2从'servergreeting'转换为'const char *'""没有用户 - 可用的定义转换操作员可以执行此转换,否则操作员无法称为"。
所以,我搜索了这个问题,发现了一些我不了解的答案。
这是代码的一些:
typedef struct server_greeting { UINT8未使用[12]; UINT32模式; UINT8挑战[16]; uint8盐[16]; UINT32计数; UINT8 MBZ [12]; } servergreeting;
struct active_session {
int socket;
// RequestSession req;
};
struct client_info {
int socket;
sockaddr_in addr;
int sess_no;
struct active_session sessions[MAX_SESSIONS_PER_CLIENT];
timeval shutdown_time;
};
static void cleanup_client (struct client_info *client)
{
fprintf (stderr,"Cleanup client %sn", inet_ntoa(client->addr.sin_addr));
FD_CLR(client->socket,&read_fds);
closesocket(client->socket);
used_sockets--;
int i;
for (i = 0; i < client->sess_no; i++)
/* If socket is -1 the session has already been closed */
if (client->sessions[i].socket > 0) {
FD_CLR(client->sessions[i].socket, &read_fds);
closesocket(client->sessions[i].socket);
client->sessions[i].socket = -1;
used_sockets--;
}
memset(client, 0, sizeof(struct client_info));
//client->status = kOffline;
}
static int send_greeting(UINT8 mode_mask, struct client_info *client)
{
int socket = client->socket;
int i;
ServerGreeting greet;
memset(&greet, 0, sizeof(greet));
greet.Modes = 1 & mode_mask;
for (i = 0; i < 16; i++)
greet.Challenge[i] = rand() % 16;
for (i = 0; i < 16; i++)
greet.Salt[i] = rand() % 16;
greet.Count = (1 << 12);
int rv = send (socket, greet, sizeof(greet), 0);
if (rv < 0) {
fprintf(stderr, "[%s] ", inet_ntoa(client->addr.sin_addr));
perror("Failed to send ServerGreeting message");
cleanup_client(client);
} else {
printf("Sent ServerGreeting message to %s. Result %dn",
inet_ntoa(client->addr.sin_addr), rv);
}
return rv;
}
你能帮我吗?谢谢
send
函数将其第二个参数a const char*
指针指向缓冲区,因此您需要使用适当的铸件传递struct
的地址,
int rv = send (socket, (const char*)&greet, sizeof(greet), 0);
编译器告诉您,它无法从您试图传递给指针类型的结构的转换,您应该相信它。