用同位素组合过滤元素

Question

我目前正在使用同位素筛选出版物列表，但希望能够将标准的、文档化的链接筛选方法与选择元素结合起来，因为我的第二个筛选列表相当长。

我正在努力处理两种不同类型的元素和，将所选值组合成一个选项数组。我可以使过滤器彼此独立工作(下面的代码)，但它们需要一起工作。如何将两个不同的操作(单击或更改)和两个属性(class=或value=)组合到一个选项数组中以传递给同位素过滤器?

    var $container = $('#library');
// select ccskills publications by default
$container.isotope({ filter: '.ccskills' });
var $optionSets = $('#library-options .option-set'),
$optionLinks = $optionSets.find('a');
$optionLinks.click(function(){
    var $this = $(this);
    // don't proceed if already selected
    if ( $this.hasClass('selected') ) {
    return false;
    }
    var $optionSet = $this.parents('.option-set');
    $optionSet.find('.selected').removeClass('selected');
    $this.addClass('selected');
    // make option object dynamically, i.e. { filter: '.my-filter-class' }
    var options = {},
    key = $optionSet.attr('data-option-key'),
    value = $this.attr('data-option-value');
    // parse 'false' as false boolean
    value = value === 'false' ? false : value;
    options[ key ] = value;
    $container.isotope( options );
    return false;
});
    // using the 'chozen' plugin to style my select element
$(".chzn-select").chosen().change(
    function() {
        var industry = $("option:selected", this).val();
        $container.isotope({filter: industry});
    }
);

Answer 1

您需要一个多维数组，每个过滤器类型都有一个数组维度。我以前做过这个，这里有一个现场演示示例!

看到!对于js.

EDIT (Feb, 2020):到演示和JavaScript的链接已经更新为2020年的回溯机器url

在我的js文件中，你会对名为getComboFilters(filters)的结束函数感兴趣

function getComboFilter( filters ) {
    var i = 0;
    var comboFilters = [];
    var message = [];
    for ( var prop in filters ) {
        message.push( filters[ prop ].join(' ') );
        var filterGroup = filters[ prop ];
        // skip to next filter group if it doesn't have any values
        if ( !filterGroup.length ) {
            continue;
        }
        if ( i === 0 ) {
            // copy to new array
            comboFilters = filterGroup.slice(0);
        }
        else {
            var filterSelectors = [];
            // copy to fresh array
            var groupCombo = comboFilters.slice(0); // [ A, B ]
            // merge filter Groups
            for (var k=0, len3 = filterGroup.length; k < len3; k++) {
                for (var j=0, len2 = groupCombo.length; j < len2; j++) {
                    filterSelectors.push( groupCombo[j] + filterGroup[k] ); // [ 1, 2 ]
                }
            }
            // apply filter selectors to combo filters for next group
            comboFilters = filterSelectors;
        }
        i++;
    }
    comboFilters.sort();
    var comboFilter = comboFilters.join(', ');
    return comboFilter;
}

这个函数处理各种过滤器数组集合的所有推入、拼接和排序，但是要使用它，你需要将它添加到过滤器例程中…我说的是例程，但它实际上是例程，因为你似乎两次单独调用过滤器方法:

$container.isotope({ filter: '.ccskills' });

,后来:

 $container.isotope({filter: .industry});

如果你要一起过滤类型，所有的过滤器类型都必须知道彼此，这意味着它们必须在同一个javascript外壳内，并且过滤器方法只需要调用一次，此时它将根据所有过滤器类型条件进行测试。

使用getComboFilter(filters)函数，像这样调用组合过滤器方法:

var $container = $('#library');
var filters = {};
var comboFilter = getComboFilter( filters );
$container.isotope({ filter: comboFilter });

最后，完全集成到您的文件中应该是这样的:

var $container = $('#library');
var filters = {};
var comboFilter = getComboFilter( filters );
$container.isotope({ filter: comboFilter });
// This next part targets all the possible filter items
// i.e. '.option-set a' just like your example
$('.option-set a').click(function(){
        // exit directly if filter already disabled
        if ($(this).hasClass('disabled') ){
            return false;
        }
        var $this = $(this);
        var $optionSet = $(this).parents('.option-set');
        var group = $optionSet.attr('data-filter-group');
        // store filter value in object
        var filterGroup = filters[ group ];
        if ( !filterGroup ) {
            filterGroup = filters[ group ] = [];
        }
        var comboFilter = getComboFilter( filters );
        $container.isotope({ filter: comboFilter });
});
function getComboFilter( filters ) {
    var i = 0;
    var comboFilters = [];
    var message = [];
    for ( var prop in filters ) {
        message.push( filters[ prop ].join(' ') );
        var filterGroup = filters[ prop ];
        // skip to next filter group if it doesn't have any values
        if ( !filterGroup.length ) {
            continue;
        }
        if ( i === 0 ) {
            // copy to new array
            comboFilters = filterGroup.slice(0);
        }
        else {
            var filterSelectors = [];
            // copy to fresh array
            var groupCombo = comboFilters.slice(0); // [ A, B ]
            // merge filter Groups
            for (var k=0, len3 = filterGroup.length; k < len3; k++) {
                for (var j=0, len2 = groupCombo.length; j < len2; j++) {
                    filterSelectors.push( groupCombo[j] + filterGroup[k] ); // [ 1, 2 ]
                }
            }
            // apply filter selectors to combo filters for next group
            comboFilters = filterSelectors;
        }
        i++;
    }
    comboFilters.sort();
    var comboFilter = comboFilters.join(', ');
    return comboFilter;
}

希望这能帮助到一些人!