Libvlc流部分屏幕

Question

我想使用vlc库流屏幕的一部分。我写了一个小例子:

#include <iostream>
#include <cstdlib>
#include <vlc/vlc.h>

int main(int argc, char**argv)
{
    libvlc_instance_t * inst = libvlc_new(argc, argv);
    libvlc_vlm_add_broadcast(inst, "mybroad",
            "screen://", "#transcode{vcodec=h264, venc=x264,vb=0,scale=0, acodec=mpga,ab=128,channels=2, samplerate=44100}:http{mux=ffmpeg{mux=flv}, dst=:7777/}",
            0, NULL, 1, 0);
    libvlc_vlm_play_media(inst, "mybroad");
    std::cout << "ready" << std::endl;
    // next two lines - it just for waitint
    int i;
    std::cin >> i;
    // omit the code that frees libvlc
    return 0;
}

这个代码流整个屏幕。我可以流式传输屏幕的一部分，如果我在控制台做:

vlc -I "dummy" screen:// --screen-left=0 --screen-top=0 
   --screen-width=640 --screen-height=480 
   --screen-fps=1 
   --sout '#transcode{vcodec=h264,vb=800,scale=1,
     acodec=mpga,ab=128,channels=2,
     samplerate=44100}:http{mux=ts,dst=:7777/}'

我试图通过修改一行代码来做到这一点:

libvlc_vlm_add_broadcast(inst, "mybroad",
                "screen:// :screen-fps=24 :screen-top=0 :screen-left=0 :screen-width=320 :screen-height=240", 
               "#transcode{vcodec=h264,venc=x264, vb=0,scale=0,acodec=mpga,ab=128,channels=2, samplerate=44100}:http{mux=ffmpeg{mux=flv},dst=:7777/}",
                0, NULL, 1, 0);

但是这个修改并没有改变什么。

老实说，我想从一个监视器(我有两个监视器)流式传输，但我可以计算监视器的边界。

Answer 1

我找到解决办法了。

#include <iostream>
#include <cstdlib>
#include <vlc/vlc.h>

int main(int argc, char**argv)
{
    // the array with parameters
    const char* params[] = {"screen-top=0", 
                            "screen-left=0",
                            "screen-width=640", 
                            "screen-height=480", 
                            "screen-fps=10"}; 
    libvlc_instance_t * inst = libvlc_new(argc, argv);
    libvlc_vlm_add_broadcast(inst, "mybroad",
            "screen://", 
            "#transcode{vcodec=h264,vb=800,scale=1,acodec=mpga,ab=128,channels=2,samplerate=44100}:http{mux=ts,dst=:7777/}",
            5, params, // <= 5 == sizeof(params) == count of parameters
            1, 0);
    libvlc_vlm_play_media(inst, "mybroad");
    std::cout << "ready" << std::endl;
    int i;
    std::cin >> i;
    return 0;
}