我使用字母表列表,用户输入关键字,关键字被索引并添加到您想要加密的文本中。但是,如果它多于一个字符,它会这样做。'ab'只会被识别为最后一个字符;用'2'代替'3'。请帮忙,提前谢谢
key = [123, 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k',
'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w',
'x', 'y', 'z']
def encrypt(k, plaintext):
result = ''
for l in k:
try:
p = (key.index(l)) %26
print p
except ValueError:
result += 1
for l in plaintext:
try:
i = (key.index(l) + p) %26
result += key[i]
print i
except ValueError:
result += l
return result.upper()
如果您正在实现Caesar密码,您可能想看看这个,它取自这里https://inventwithpython.com/chapter14.html
MAX_KEY_SIZE = 26
def getMode():
while True:
print('Do you wish to encrypt or decrypt a message?')
mode = input().lower()
if mode in 'encrypt e decrypt d'.split():
return mode
else:
print('Enter either "encrypt" or "e" or "decrypt" or "d".')
def getMessage():
print('Enter your message:')
return input()
def getKey():
key = 0
while True:
print('Enter the key number (1-%s)' % (MAX_KEY_SIZE))
key = int(input())
if (key >= 1 and key <= MAX_KEY_SIZE):
return key
def getTranslatedMessage(mode, message, key):
if mode[0] == 'd':
key = -key
translated = ''
for symbol in message:
if symbol.isalpha():
num = ord(symbol)
num += key
if symbol.isupper():
if num > ord('Z'):
num -= 26
elif num < ord('A'):
num += 26
elif symbol.islower():
if num > ord('z'):
num -= 26
elif num < ord('a'):
num += 26
translated += chr(num)
else:
translated += symbol
return translated
mode = getMode()
message = getMessage()
key = getKey()
print('Your translated text is:')
print(getTranslatedMessage(mode, message, key))