如何使用docopt传递多个参数

Question

我想使用docopt将两个强制参数和一个可选参数传递给我的程序。我使用的代码是：

"""Setup
Usage: myprog.py server_name config [--help] [options] 
Arguments:
    SERVER_NAME        Server Name (a1, a2)
    CONFIG             Config file with full path
Options:
    -h --help
    -r --start      Start the server if yes [default: 'no']
"""
from docopt import docopt
class ServerSetup(object):
    def __init__(self, server_name, config_file, start_server):
        self.server = server_name
        self.config = config_file
        self.start_server = start_server
    def print_msg(self):
        print self.server
        print self.config
        print self.start_server
if __name__ == '__main__':
    args = docopt(__doc__)
    setup = ServerSetup(server_name=args['SERVER_NAME']),
                        config=args['CONFIG']
                        start_rig=args['-r'])
    setup.print_msg()

$python myprog.py a1/abc/file1.txt

当我使用上面的命令运行上面的程序时，我会收到一条错误消息，显示我所写的用法。这里出了什么问题，我如何使用多个"Arguments"？

Answer 1

将参数封装在<…>中，否则，它们只是被当作命令来威胁。这应该有效：

"""Setup
Usage: myprog.py [options] <SERVER_NAME> <CONFIG>
Arguments:
    SERVER_NAME        Server Name (a1, a2)
    CONFIG             Config file with full path
Options:
    -h, --help
    -r, --start        Start the server if yes [default: 'no']
"""
from docopt import docopt
class ServerSetup(object):
    def __init__(self, server_name, config_file, start_server):
        self.server = server_name
        self.config = config_file
        self.start_server = start_server
    def print_msg(self):
        print self.server
        print self.config
        print self.start_server
if __name__ == '__main__':
    args = docopt(__doc__)
    print args
    setup = ServerSetup(server_name=args['<SERVER_NAME>'],
                        config_file=args['<CONFIG>'],
                        start_server=args['--start'])
    setup.print_msg()