它应该打印fibonacci系列直至位置,但它只是打印1 1 2,即使我要求的是前三个元素。我该如何解决?
#include <iostream>
using std::cout;
using std::cin;
int main()
{
cout << "Enter a number: ";
int number;
cin >> number;
int count = 1;
int a = 1; //The first number of the Fibonacci's serie is 1
int b = 1; //The second number of the Fibonacci's serie is 2
while (count <= number)
{
if (count < 3)
cout << "1 ";
else
{
number = a + b; //Every number is the sum of the previous two
cout << number << " ";
if (count % 2 == 1)
a = number;
else
b = number;
}
count++;
}
return 0;
}
您正在使用number
作为循环迭代的最大数量:
while (count <= number)
,但是在循环中,您使用的变量与当前的fib值相同,以便每次迭代输出。
number = a + b; //Every number is the sum of the previous two
cout << number << " ";
这会导致循环过早终止。您需要为这两个不同的值选择不同的变量名称。
它就像交换变量的值。您正在使用该数字作为限制,但是在循环中,您正在使用相同的变量,该变量正在创建逻辑错误。进行以下更改,然后完成(Y(。
int main()
{
cout << "Enter a number: ";
int number;
cin >> number;
int count = 1;
int a = 1; //The first number of the Fibonacci's serie is 1
int b = 1;
int i = 1; //The second number of the Fibonacci's serie is 2
while (i <= number)
{
if (i < 3)
cout << "1 ";
else
{
count = a + b; //Every number is the sum of the previous two
a = b;
b = count;
cout << count << " ";
}
i++;
}
return 0;
}
您可以尝试此代码:
int main()
{
int n, t1 = 0, t2 = 1, nextTerm = 0;
cout << "Enter the number of terms: ";
cin >> n;
cout << "Fibonacci Series: ";
for (int i = 1; i <= n; ++i)
{
// Prints the first two terms.
if(i == 1)
{
cout << " " << t1;
continue;
}
if(i == 2)
{
cout << t2 << " ";
continue;
}
nextTerm = t1 + t2;
t1 = t2;
t2 = nextTerm;
cout << nextTerm << " ";
}
return 0;
}