我是 Sql 的新手,所以不确定我做错了什么。
我有两个表:
Tbl 1 中的数据
EmpID---------PrdcType-------EmpName
1000 -------- A -------------X1
2000 -------- B -------------X2
1000 -------- A -------------X1
3000 -------- A -------------X3
so on.....
TbL 2 中的数据
EmpID-------ExPrdc--------EmpName
2000 ------ A -------------X2
3000 ------ B -------------X3
1000 ------ A -------------X1
1000 ------ A -------------X1
So on...
结果应为:
EmpName--------EmpID--------Table1_A_Prdc_Count--------Table2_A_Prdc_Count
X1-------------1000---------2---------------------------2
X2-------------2000---------0---------------------------1
X3-------------3000---------1---------------------------0
So on..
但我得到:
EmpName--------EmpID--------Table1_A_Prdc_Count--------Table2_A_Prdc_Count
X1-------------1000---------1547-----------------------------------2131
X2-------------2000---------321------------------------------------987
X3-------------3000---------46546----------------------------------3265465
这些数字是完全随机的,但每次的数字都是相同的,除非我将 0 值更改为 null 或任何其他值。我尝试检查模式,但没有用。
我正在使用的代码:
select r.EmpName,r.EmpID,
count(CASE WHEN d.PrdcType='A' Then 1 else 0 END) as Table1_A_Prdc_Count,
COUNT(CASE WHEN r.ExPrdc='A' Then 1 else 0 END) as CAL
from Tbl1 r
INNER join Tbl2 d on r.EmpID= d.EmpID
where r.EmpID in('X1','X2','X3') and d.EmpID in ('X1','X2','X3')
group by r.EmpName,r.EmpID,d.EmpID,d.EmpName
当我使用相同的代码而不进行内部连接(将其分别用于不同的表(时,我得到了正确的结果,但是一旦我添加内部连接,它就不起作用。请帮助我,因为我被困了 2 个多星期。提前谢谢你。
SQL 演示
您当前的查询有几个问题,实际上它不会运行。您可以通过实施一个简单的想法来获得所需的结果。
使用查询从Tbl1
中计数A
,从Tbl2
使用另一个查询中计数A
,然后按如下所示JOIN
它们:
select r.EmpName, r.EmpID, Table1_A_Prdc_Count, Table2_A_Prdc_Count
from
(
select EmpName, EmpID,
sum(CASE WHEN PrdcType='A' Then 1 else 0 END) as Table1_A_Prdc_Count
from Tbl1 d
where d.EmpName in('X1','X2','X3')
group by EmpName, EmpID
) as d
join
(
select EmpName, EmpID,
sum(CASE WHEN ExPrdc='A' Then 1 else 0 END) as Table2_A_Prdc_Count
from Tbl2
where EmpName in('X1','X2','X3')
group by EmpName, EmpID
) as r on d.EmpID = r.EmpID and d.EmpName = r.EmpName
输出
EmpName EmpID Table1_A_Prdc_Count Table2_A_Prdc_Count
-----------------------------------------------------------
X1 1000 2 2
X2 2000 0 1
X3 3000 1 0
不仅仅是产品 A
的完整计数让我考虑一下
select a.*, b.cnt as cntB
from ( select r.EmpName, r.EmpID, count(*) as cnt
from Tbl1 r
where r.EmpID in('X1','X2','X3')
group by r.EmpName, r.EmpID
) a
join ( select d.EmpName, d.EmpID, count(*) as cnt
from TbL 2 d
where d.EmpID in('X1','X2','X3')
group by d.EmpName, d.EmpID
) b
on a.EmpID = b.EmpID
仅限产品 A
select isnull(a.EmpName, b.EmpName) as name
, isnull(a.EmpID, b.EmpID) as id
, isnull(a.cnt, 0) as cntA
, isnull(b.cnt, 0) as cntB
from ( select r.EmpName, r.EmpID, count(*) as cnt
from Tbl1 r
where r.EmpID in('X1','X2','X3')
and PrdcType = 'A'
group by r.EmpName, r.EmpID
) a
full outer join
( select d.EmpName, d.EmpID, count(*) as cnt
from TbL 2 d
where d.EmpID in('X1','X2','X3')
and ExPrdc = 'A'
group by d.EmpName, d.EmpID
) b
on a.EmpID = b.EmpID
order by isnull(a.EmpID, b.EmpID)