当用户访问时,我会将IP地址和他们访问的时间保存到文本文件中(这是受保护的,不能公开访问(。
PHP是:
<?php
$file = "ipaddresses.txt";
$timestamp =date('l jS of F Y h:i:s A');
$f=fopen($file, 'a+');
fwrite($f,$_SERVER['REMOTE_ADDR'], $timestamp."n");
fclose($f);
?>
我想我只是将第二个timestamp
标签放置在错误的位置,但似乎无法使用REMOTE ADDR
弄清楚,即使我用其他表单节省了时间,只是一次发布所有输入。
似乎很简单,但我迷路了,所以任何帮助将不胜感激。
EDIT 1:
请参阅更新的代码;
<?php
$file = "ipaddresses.txt";
$timestamp =date('l jS of F Y h:i:s A');
$f=fopen($file, 'a+');
$info = $_SERVER['REMOTE_ADDR'] . $timestamp . "n";
fwrite($f, $info);
fclose($f);
?>
fwrite()
只需要两个参数:文件和要写入的信息。
因此,您可能希望将 IP 和时间戳连接为一个字符串:
fwrite($f, $_SERVER['REMOTE_ADDR'] . $timestamp . "n");
或:
$info = $_SERVER['REMOTE_ADDR'] . $timestamp . "n";
fwrite($f, $info);
function getRealIpAddr(){
if(isset($_SERVER["HTTP_CF_CONNECTING_IP"])){
$_SERVER['REMOTE_ADDR'] = $_SERVER["HTTP_CF_CONNECTING_IP"];
$_SERVER['HTTP_CLIENT_IP'] = $_SERVER["HTTP_CF_CONNECTING_IP"];
}
$client = @$_SERVER['HTTP_CLIENT_IP'];
$forward = @$_SERVER['HTTP_X_FORWARDED_FOR'];
$remote = $_SERVER['REMOTE_ADDR'];
if(filter_var($client, FILTER_VALIDATE_IP)){
$ip = $client;
} elseif(filter_var($forward, FILTER_VALIDATE_IP)){
$ip = $forward;
} else{
$ip = $remote;
}
return $ip;
}
$Ip_Address = getRealIpAddr();
$Timestamp = date("Y-m-d H:i:s");
$array = array("IP"=>$Ip_Address,"Timestamp"=>$Timestamp);
$myfile = fopen("ipaddresses.txt", "a+") or die("Unable to open file!");
fwrite($myfile, json_encode($array));
fclose($myfile);
<?php
$file = "ipaddresses.txt";
$timestamp =date('l jS of F Y h:i:s A');
$f=fopen($file, 'a+');
$info = $_SERVER['REMOTE_ADDR'] . $timestamp . "n";
fwrite($f, $info);
fclose($f);
?>