比较 2 个文本文件并找到列表中的差异，并找出哪些列表值不匹配

Question

我正在使用扫描仪读取 2 个文本文件(可能包含重复项(并将它们写入 arraylist。我正在比较两个数组列表以找到差异。当我打印出来时，我可以看到有什么区别，但我不知道哪个记录来自哪个文件(文本文件名(

文本内容1.txt

TIMESTAMP,FE,TDI,20190703113119,20190601000000,20190701000000,
TIMESTAMP,FE,KYMI,20190703113130,20190601000000,20190701000000,
TIMESTAMP,FE,UMRI,20190703113154,20190601000000,20190701000000,
TIMESTAMP,FE,MLI,20190703113211,20190601000000,20190701000000,
TIMESTAMP,FE,WOLI,20190703113221,20190601000000,20190701000000,
TIMESTAMP,FE,VEM,20190703113221,20190601000000,20190701000000,
TIMESTAMP,FE,ZER,20190703113154,20190601000000,20190701000000,

文本内容2.txt

TIMESTAMP,FE,TDL,20190703113119,20190601000000,20190701000000,
TIMESTAMP,FE,KYMA,20190703113130,20190601000000,20190701000000,
TIMESTAMP,FE,UMRC,20190703113154,20190601000000,20190701000000,
TIMESTAMP,FE,MLW,20190703113211,20190601000000,20190701000000,
TIMESTAMP,FE,WOLF,20190703113221,20190601000000,20190701000000,
TIMESTAMP,FE,VEM,20190703113221,20190601000000,20190701000000,
TIMESTAMP,FE,ZER,20190703113154,20190601000000,20190701000000,

法典：

Scanner prodScanner = new Scanner(prodFile);
while (prodScanner.hasNextLine()) {
String currentRecord = prodScanner.nextLine().trim(); 
if (currentRecord.length() > 0) {
prodRecordsFromStatement.add(currentRecord);
}
}
Scanner nonProdScanner = new Scanner(nonProdFile);
while (nonProdScanner.hasNextLine()) {
String currentRecord = nonProdScanner.nextLine().trim();  
if (currentRecord.length() > 0) {                                   
nonProdRecordsFromStatement.add(currentRecord);
}
}
Collection<String> result = new ArrayList<>(CollectionUtils.disjunction(prodRecordsFromStatement, nonProdRecordsFromStatement));
List<String> resultList = new ArrayList<>(result);
Collections.sort(resultList);

实际结果：

TIMESTAMP,FE,KYMA,20190703113130,20190601000000,20190701000000,
TIMESTAMP,FE,KYMI,20190703113130,20190601000000,20190701000000,
TIMESTAMP,FE,MLI,20190703113211,20190601000000,20190701000000,
TIMESTAMP,FE,MLW,20190703113211,20190601000000,20190701000000,
TIMESTAMP,FE,TDI,20190703113119,20190601000000,20190701000000,
TIMESTAMP,FE,TDL,20190703113119,20190601000000,20190701000000,
TIMESTAMP,FE,UMRC,20190703113154,20190601000000,20190701000000,
TIMESTAMP,FE,UMRI,20190703113154,20190601000000,20190701000000,
TIMESTAMP,FE,WOLF,20190703113221,20190601000000,20190701000000,
TIMESTAMP,FE,WOLI,20190703113221,20190601000000,20190701000000,

预期成果： 我希望显示文件/列表的名称以便于理解

text2.txt,TIMESTAMP,FE,KYMA,20190703113130,20190601000000,20190701000000,
text1.txt,TIMESTAMP,FE,KYMI,20190703113130,20190601000000,20190701000000,
text1.txt,TIMESTAMP,FE,MLI,20190703113211,20190601000000,20190701000000,
text2.txt,TIMESTAMP,FE,MLW,20190703113211,20190601000000,20190701000000,
text1.txt,TIMESTAMP,FE,TDI,20190703113119,20190601000000,20190701000000,
text2.txt,TIMESTAMP,FE,TDL,20190703113119,20190601000000,20190701000000,
text2.txt,TIMESTAMP,FE,UMRC,20190703113154,20190601000000,20190701000000,
text1.txt,TIMESTAMP,FE,UMRI,20190703113154,20190601000000,20190701000000,
text2.txt,TIMESTAMP,FE,WOLF,20190703113221,20190601000000,20190701000000,
text1.txt,TIMESTAMP,FE,WOLI,20190703113221,20190601000000,20190701000000,

Answer 1

遍历resultList检查以查看当前项目是否也在prodRecordsFromStatement中。

如果是这样，则它来自文件 1，否则来自文件 2。

Answer 2

您的解决方案需要多大的性能？ 如果性能不是非常关键，并且您的列表不长，那么您可以切换到使用subtract而不是析取。

例如

Collection<String> resultProdRecords = new ArrayList<>(CollectionUtils.subtract(prodRecordsFromStatement, nonProdRecordsFromStatement));
Collection<String> resultNonProdRecords = new ArrayList<>(CollectionUtils.subtract(prodRecordsFromStatement, nonProdRecordsFromStatement));

resultProdRecords将包含 prodRecordsFromStatement 中不在非 ProdRecordFromStatement 中的所有行。

resultNonProdRecords将包含非 ProdRecordFromStatement 中所有不在 prodRecordsFromStatement 中的行。