如何在Laravel 5中链接递归数据剪裁

Question

我正在制作一个具有递归结构的模型，如下所示。概念模型可以具有父母和子女概念，并且该模型按预期工作。我的问题是实施一个页面以添加两个概念之间的链接。

<?php
namespace AppModels;
use IlluminateDatabaseEloquentModel;
class Concept extends Model
{
    //
    public function parentConcepts()
    {
        return $this->belongsToMany('AppModelsConcept','concept_concept','parent_concept_id','child_concept_id');
    }
    public function childConcepts()
    {
        return $this->belongsToMany('AppModelsConcept','concept_concept','child_concept_id','parent_concept_id');
    }
    public function processes()
    {
        return $this->hasMany('AppModelsProcess');
    }
}

我该怎么做？我会在模型中利用枢轴属性，还是会为concept_concept表创建新的模型和控制器？任何帮助将不胜感激！

Answer 1

在控制器中创建一个新功能，该功能使用the attach（）函数是该解决方案的关键。

public function storeChildLink(Request $request)
{
    //get the parent concept id
    $concept = Concept::find($request->input('parentConceptId'));
    //attach the child concept
    $concept->childConcepts()->attach($request->input('childConceptId'));
    $concept->save();
    return redirect()->route('concept.show', ['id' => $request['parentConceptId']])->with('status', 'Child Concept Successfully Linked');
}
public function storeParentLink(Request $request)
{
    //get the child concept id
    $concept = Concept::find($request->input('childConceptId'));
    //attach the parent concept
    $concept->parentConcepts()->attach($request->input('parentConceptId'));
    $concept->save();
    return redirect()->route('concept.show', ['id' => $request['childConceptId']])->with('status', 'Parent Concept Successfully Linked');
}