test = 'x02m@x0ex00'
print(test)
print(test.replace('╗m@', "first"))
new_test = test.encode('raw_unicode_escape').decode('utf-8')
print(new_test)
print(new_test.replace('╗m@', "second"))
again_new = new_test.encode('raw_unicode_escape').decode('utf-8')
print(again_new)
print(again_new.replace('╗m@', "third"))
我一直在尝试解密一些最初使用 python 3.6 通过 VB.Net 加密的文件;该文件在编码到 base 64 之前是用公钥加密的。我已经尝试了多种方法来解码 base 64 并使用给出的私钥对其进行解密，但是，我总是会有一些特殊字符，例如"╗m@"，即使我尝试手动删除它们也无法删除。
我也尝试通过"utf-8"和"ascii"进行解码，但无济于事。我尝试环顾四周，有些人告诉我它看起来像一个双重编码的字符串，但是，即使解码两次，我似乎也无法替换字符串。
据我所知，'\x02m@\x0e\x00' 在运行时会返回'╗m@'。字符串不能直接解码，因此，我在解码之前使用"raw_unicode_escape"将字符串更改为字节对象。
如果有人能指出我应该朝哪个方向前进，将不胜感激。谢谢。
import Crypto
from Crypto.PublicKey import RSA
import base64
import codecs
import re
# reading private key
rsa_key = RSA.importKey(open('PrivateKey.pem', 'r').read())
# reading the file that is suppose to be decrypted
file = open('test.txt', 'r')
message = file.read()
# decode base64 first
decrypted_body = base64.b64decode(message)
print(decrypted_body)
# have to make it bytearray if not, it would not be able to concat with the decrypted chunk
final_decrypted = bytearray()
# size of the chunk to decrypt
chunk_size = 128
offset = 0
# maximum length of the body that has to be decrypted
limit = len(decrypted_body)
# there is a need to check the length that has to be decrypted so as to not overshot during the last iteration
while offset < len(decrypted_body):
if (offset + chunk_size > limit):
copyLength = limit
else:
copyLength = offset + chunk_size
chunk = decrypted_body[offset: copyLength]
final_decrypted += rsa_key.decrypt(chunk)
offset += chunk_size
# decode the result to utf-8 to remove bytes that can't be read
xml_decrypted = codecs.decode(final_decrypted, encoding = 'utf-8', errors = 'ignore')
break_loop = False
remove_arr = []
# pattern to find the special character in what was decoded
pattern = re.compile('[^0-9a-zA-Z<>_="?. -/@:™{^\r}{^\n}]+')
for i in range(0, len(xml_decrypted)):
if (pattern.match(xml_decrypted[i])):
arr = []
arr.append(xml_decrypted[i])
# x00 refer to " " thus, I do not want to remove it as it would make the xml harder to read
# this is to append all the special symbol into an array
while (xml_decrypted[i] != 'x00' and i < len(xml_decrypted)):
n = i
i += 1
if (i < len(xml_decrypted)):
arr.append(xml_decrypted[i])
else:
break_loop = True
break
remove_str = "".join(arr)
remove_arr.append(remove_str)
i = n
if (break_loop):
break
# check if the array has any " " inside as there is no need to remove space from the xml result
# remove each of the result inside the array from the decoded result which will hopefully return me the xml without any special symbol
new_str = ""
remove_arr = [x for x in remove_arr if x != 'x00']
for each in remove_arr:
print(str(each))
new_str = xml_decrypted.replace(each, '')
xml_decrypted = new_str
print(xml_decrypted)
根据要求，我已经在这里发布了我的 python 3 代码，但我无法发布 VB.Net 代码，因为它不属于我。干杯
您使用的是原始或教科书式的RSA。从decrypt文档中：
注意：此函数执行普通、原始的 RSA 解密(教科书(。在实际应用中，您始终需要使用适当的加密填充，并且不应使用此方法直接解密数据。否则可能会导致安全漏洞。建议改用模块
Crypto.Cipher.PKCS1_OAEP或Crypto.Cipher.PKCS1_v1_5。
因此，您可能忘记从结果中删除(主要是随机的(填充。我会先尝试PKCS1_v1_5。
强烈建议使用混合加密(例如AES/GCM与RSA OAEP结合使用(，而不是使用相同的RSA密钥进行多次加密。