我正试图创建一个数组数组,其结构为8x8,其中每个单元格都是3x3数组。我所创造的东西是有效的,但当我想更改特定的值时,我需要以不同于预期的方式访问它。
import numpy as np
a = np.zeros((3,3))
b = np.array([[0,1,0],[1,1,1],[0,1,0]])
d = np.array([[b,a,b,a,b,a,b,a]])
e = np.array([[a,b,a,b,a,b,a,b]])
g = np.array([[d],[e],[d],[e],[d],[e],[d],[e]])
#Needed to change a specific cell
#g[0][0][0][0][0][0] = x : [Row-x][0][0][Cell-x][row-x][cell-x]
#Not sure why I have to have the 2 0's between the Row-x and the Cell-x identifiers
之后,我需要将每个值映射到24x24网格,其中1的颜色与0的颜色不同。如果有人能为实现这一目标提供指导,我们将不胜感激。不是在寻找具体的代码,而是了解如何做到这一点的基础。
感谢
In [291]: a = np.zeros((3,3))
...: b = np.array([[0,1,0],[1,1,1],[0,1,0]])
...: d = np.array([[b,a,b,a,b,a,b,a]])
...: e = np.array([[a,b,a,b,a,b,a,b]])
...: g = np.array([[d],[e],[d],[e],[d],[e],[d],[e]])
In [292]: a.shape
Out[292]: (3, 3)
In [293]: b.shape
Out[293]: (3, 3)
d
为4d-计算括号:[[....]]
:
In [294]: d.shape
Out[294]: (1, 8, 3, 3)
In [295]: e.shape
Out[295]: (1, 8, 3, 3)
g
是4个暗元素的(8,1(,共6个。再次计算括号:
In [296]: g.shape
Out[296]: (8, 1, 1, 8, 3, 3)
访问2d子阵列,在这种情况下等于b
:
In [298]: g[0,0,0,0,:,:]
Out[298]:
array([[0., 1., 0.],
[1., 1., 1.],
[0., 1., 0.]])
重做,没有多余的括号:
In [299]: a = np.zeros((3,3))
...: b = np.array([[0,1,0],[1,1,1],[0,1,0]])
...: d = np.array([b,a,b,a,b,a,b,a])
...: e = np.array([a,b,a,b,a,b,a,b])
...: g = np.array([d,e,d,e,d,e,d,e])
In [300]: d.shape
Out[300]: (8, 3, 3)
In [301]: g.shape
Out[301]: (8, 8, 3, 3)