onItemClick将项目id传递给intent

Question

我从第一个意图中打印出正确的id，但没有正确发送给第二个意图。

第一个意图的项目点击:(对于以后的观众，这个问题已经更新了正确的答案):

    gridView.setOnItemClickListener(new OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> a, View v, int i, long l) {
            Intent intent = new Intent(videoChannelActivity.this,
                    PlayVideoActivity.class);
            intent.putExtra("videoId", l);
            System.out.println("video id intent1 = " + l);
            startActivity(intent);
        }
    });

log: 05-08 17:40:40.505: I/System.out(13938): video id intent 1: 2

第二意图创建:

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    final VideoView videoView;
    setContentView(R.layout.activity_play_video);
    Bundle extras;
    long videoLong;
    if (savedInstanceState == null) {
        extras = getIntent().getExtras();
        if (extras == null) {
            videoLong = 0;
        } else {
            videoLong = extras.getLong("videoId");
            System.out.println("video id intent 2 =  " + videoLong);
        }
    }

log: 05-08 17:46:19.166: I/System.out(14382): video id intent 2 = null

Answer 1

l 是类型的长…

所以你需要提取long而不是像

那样的String

 videoLong = extras.getLong("videoId");

所以第二个意图的完整实现是

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    final VideoView videoView;
    setContentView(R.layout.activity_play_video);
    Bundle extras;
    Long videoLong;
    if (savedInstanceState == null) {
        extras = getIntent().getExtras();
        if (extras == null) {
            videoLong= null;
        } else {
            videoLong= extras.getLong("videoId");
            System.out.println("video id intent 2 =  " + videoLong);
        }
    }

Answer 2

您正在传递long作为额外的，但试图将其读取为String.