我试图在lua项目上使用bust进行单元测试。我有一个模块,看起来像这样:
-- src/rom/apis/display.lua
local _displayModes = {
single = 1,
mirrored = 2,
extended = 3,
immersive = 4
}
local _validMode = function(mode)
retVal = false
for k,v in pairs(_displayModes) do
if mode == v then retVal = true break end
end
return retVal
end
local _setMode = function (mode)
if _validMode(mode) then
_config.mode = mode
else
error("INVALID DISPLAY MODE: "..mode)
end
end
display = {
mode = _displayModes,
setMode = _setMode
}
在我的规范我试图断言setMode返回一个错误:
local displayModule = require("rom/apis/display")
describe("#API #Display", function()
describe("with single monitor", function()
setup(function()
local _p = {
monitor = {'foo'}
}
mockPeripherals(_p)
end)
it("should not setMode with invalid mode", function()
assert.has_error(display.setMode(100), "INVALID DISPLAY MODE: 100")
end)
end)
end)
当我运行规格时,由于函数中的错误,它出错了。下面是控制台输出:
$ busted ●●●●✱ 4 successes / 0 failures / 1 error / 0 pending :
0.001444 seconds
Error → test/spec/rom/apis/display_spec.lua @ 32
#API #Display with single monitor should not setMode with invalid mode ./src/rom/apis/display.lua:32: INVALID DISPLAY MODE: 100
stack traceback: ./src/rom/apis/display.lua:32: in function 'fn' test/spec/rom/apis/display_spec.lua:34: in function <test/spec/rom/apis/display_spec.lua:32>
它与我期望的错误错误,但问题是测试应该通过,因为我断言它正在返回正确的错误。
您需要在函数中封装错误调用:
it("should not setMode with invalid mode", function()
assert.has_error(function() display.setMode(100) end, "INVALID DISPLAY MODE: 100")
end)