WebSocket convertAndSendToUser无法接收到消息

Question

我使用websocket发送消息到客户端，当使用这个方法广播消息到客户端。

private void pushInfoImpl(String url, String content) {
    if (simpMessagingTemplate != null) {
        simpMessagingTemplate.convertAndSend(url, content);
    }
}

客户端可以成功接收到消息。当使用此方法发送指定用户:

//send url:/queue/location
//user:admin
 private void pushInfoImpl(String user, String url, String content) {
    if (simpMessagingTemplate != null) {
        simpMessagingTemplate.convertAndSendToUser(user, url, content);
    }
}

客户端无法接收发送的消息。我试过的:

1. 在config.enableSimpleBroker("/topic","/queue");
中添加队列
2. 订阅url，如stompClient.subscribe('/admin/queue/location', function (greeting) { console.log(greeting.body); }); .admin为用户。

我该怎么做来解决这个问题?使客户端成功接收到服务器消息。日志:

15:03:28.806]-[Timer-5699]-[org.springframework.messaging.simp.broker.SimpleBrokerMessageHandler]-{Processing MESSAGE destination=/queue/location-userdeqnkwuw session=null payload={"data":[{"status":2,"vehicleId":"cae21196-cb66-4256-88a6-7cdfb23e2c78"}],"desc"...(truncated)}
            15:03:28.806]-[Timer-5701]-[org.springframework.messaging.simp.broker.SimpleBrokerMessageHandler]-{Processing MESSAGE destination=/queue/location-userdeqnkwuw session=null payload={"data":[{"status":2,"vehicleId":"cae21196-cb66-4256-88a6-7cdfb23e2c78"}],"desc"...(truncated)}
            15:03:28.806]-[Timer-5699]-[org.springframework.messaging.simp.broker.SimpleBrokerMessageHandler]-{Processing MESSAGE destination=/queue/location-userdeqnkwuw session=null payload={"data":[{"status":2,"vehicleId":"cae21196-cb66-4256-88a6-7cdfb23e2c78"}],"desc"...(truncated)}

Answer 1

原因是url不正确，在服务器上，发送参数应该是这样的:

user: admin
url: /location(right) vs /queue/location(wrong)

在客户端

上，订阅者应该像这样:

/user/admin/location or /user/{username}/location