如何在php中删除大括号

Question

我有一个变量美元uuid = {" uuid":" 28 fb72ed 4 - 0 - e97 e78 - 9404 b676289b33ee "};

执行后得到的

我需要提取28fb72ed-0e97-4e78-9404-b676289b33ee只是数字

如何在PHP中实现

我在这里包含了一些代码我正在使用crocodoc查看器，我已经使用鳄鱼API生成了流体现在检查状态，我需要液体单独…它传递的是整个变量我必须分开并单独获得uid

    $ch = curl_init(); 
                @curl_setopt($ch, CURLOPT_HEADER, 0);
                @curl_setopt($ch, CURLOPT_HTTPHEADER,  array('Accept: application/json', 'X-HTTP-Method-Override: POST'));
                @curl_setopt($ch, CURLOPT_POST, 1);
                @curl_setopt($ch, CURLOPT_POSTFIELDS,$param);
                @curl_setopt($ch, CURLOPT_URL, $frameUrl);   
                @curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
                @curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
                curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0);
                curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, 0);
                $uuids = curl_exec($ch);
 echo $uuids;
 echo "nnchecking status of : ", $uuids;
$status =getStatus($uuids,$api_url,$myToken);

可能此处应该使用regex或explosion()或implode()函数

有人能帮帮我吗?

谢谢

Answer 1

2个解

使用JSON更容易:

$str = '{"uuid": "28fb72ed-0e97-4e78-9404-b676289b33ee"}';
$obj  = json_decode($str);
echo $obj->uuid;

输出:

28fb72ed-0e97-4e78-9404-b676289b33ee

Second with Regex

$str = '{"uuid": "28fb72ed-0e97-4e78-9404-b676289b33ee"}';
preg_match('/"uuid": "([^"]+?)"/', $str, $matches);
print_r($matches);

输出:

Array ( [0] => "uuid": "28fb72ed-0e97-4e78-9404-b676289b33ee" [1] => 28fb72ed-0e97-4e78-9404-b676289b33ee )

$matches[1]有你需要的价值

Answer 2

Try with

 echo $uuid->uuid;

Answer 3

下面的代码将解决您的错误:

preg_replace('/{}/', '', $uuids);