正则表达式模式可选组，具体取决于空格

Question

我对正则表达式很陌生，我需要创建一个可用于匹配不同文本值(案例(的模式。我可以使用创建的模式，但它只能在一种情况下使用。我想最大化搜索模式，以便它可以用于不同的搜索文本。

顺便说一下，我正在使用Java 8。

目的：
按组显示 matcher.find((。

示例搜索文本和预期输出(组(：

Search Text: "employeeName:*borgy*";
Expected Output:
-
(employeeName) (:) (*) (borgy) (*)
-
Search Text: "employeeName:Borgy Manotoy*";
Expected Output:
-
(employeeName) (:) () (Borgy Manotoy) (*)
-
Search Text: "employeeName:*Borgy Manotoy*";
Expected Output:
-
(employeeName) (:) (*) (Borgy Manotoy) (*)
-
Search Text: "employeeEmail:*[e-mail]*";
Expected Output:
-
(employeeEmail) (:) (*) ([e-mail]) (*)
-
Search Text: "employeeEmail:[e-mail]";
Expected Output:
-
(employeeEmail) (:) () ([e-mail]) ()
-
Search Text: "employeeName:*Manotoy*, employeeEmail:*@iyotbihagay.*";
Expected Output: 
-
(employeeName) (:) (*) (Manotoy) (*)
(employeeEmail) (:) (*) (@iyotbihagay.com) (*)
-
Search Text: "employeeName:*Manotoy*, employeeEmail:*@iyotbihagay.*, employeeRole:*bouncer*";
Expected Output: 
-
(employeeName) (:) (*) (Manotoy) (*)
(employeeEmail) (:) (*) (@iyotbihagay.com) (*)
(employeeRole) (:) (*) (bouncer) (*)
-

搜索模式：

String searchPattern = "(\w+?)(:|!)(\p{Punct}?)(\w+?) (.+?)?(\p{Punct}?),";

示例搜索文本：

String text1  = "employeeName:borgy";
String text2  = "employeeName:Borgy*";
String text3  = "employeeName:*borgy*";
String text4  = "employeeName:*Borgy*";
String text5  = "employeeName:*Borgy Manotoy*";
String text6  = "employeeEmail:*[e-mail]*";
String text7  = "employeeEmail:[e-mail]";
String text8  = "employeeEmail:borgymanotoy@iyotbihagay.*";
String text9  = "employeeEmail:*@iyotbihagay.*";
String text10 = "employeeName:*Manotoy*, employeeEmail:*@iyotbihagay.*";

使用给定模式搜索文本：

processUserSearch(text1, searchPattern);
processUserSearch(text2, searchPattern);
processUserSearch(text3, searchPattern);
...
processUserSearch(text10, searchPattern);

找到显示

private void processUserSearch(String searchText, String searchPattern) {
    if (!Util.isEmptyOrNull(searchText) && !Util.isEmptyOrNull(searchPattern)) {
        Pattern pattern = Pattern.compile(searchPattern);
        Matcher matcher = pattern.matcher(searchText + ",");
        while(matcher.find()) {
            System.out.println("[matcher-count]: " + matcher.groupCount());
            System.out.print("found: ");
            for (int x = 1; x <= matcher.groupCount(); x++) {
                System.out.print("(" + matcher.group(x) + ") ");
            }
            System.out.println("n");
        }
    }
}

Answer 1

我建议使用

private static final Pattern pattern = Pattern.compile("(\w+)([:!])(\p{Punct}?)(.*?)(\p{Punct}?)(?=$|,)");
private static void processUserSearch(String searchText) {
    if (!searchText.isEmpty() && searchText != null) {
    //if (!Util.isEmptyOrNull(searchText) && !Util.isEmptyOrNull(searchPattern)) {
        Matcher matcher = pattern.matcher(searchText);
        while(matcher.find()) {
            System.out.println(searchText + "n[matcher-count]: " + matcher.groupCount());
            System.out.print("found: ");
            for (int x = 1; x <= matcher.groupCount(); x++) {
                System.out.print("(" + matcher.group(x) + ") ");
            }
            System.out.println("n");
        }
    }
}

请注意，您可以在匹配方法之外编译一次，以提高效率。

用作

String[] texts  = new String[] { "employeeName:*borgy*","employeeName:Borgy Manotoy*","employeeName:*Borgy Manotoy*",
                           "employeeEmail:*[e-mail]*","employeeEmail:[e-mail]",
                           "employeeName:*Manotoy*, employeeEmail:*@iyotbihagay.*",
                           "employeeName:*Manotoy*, employeeEmail:*@iyotbihagay.*, employeeRole:*bouncer*"};
for (String s: texts) {
        processUserSearch(s);
    }
}

查看 Java 演示

这是正则表达式演示：

(w+)([:!])(p{Punct}?)(.*?)(p{Punct}?)(?=$|,)

详

• (w+) - 第 1 组：一个或多个单词字符
• ([:!]) - 第2组：:或!
• (p{Punct}?) - 第 3 组：可选的标点符号
字符
• (.*?) - 第 4 组：除换行符字符以外的任何 0+ 字符
• (p{Punct}?) - 第 5 组：可选的标点符号
字符
• (?=$|,) - 字符串或,的末尾应紧邻当前位置的右侧(但它们不会添加到匹配值中，因为它是积极的展望(。

Answer 2

我想最大化搜索模式，以便它可以用于不同的搜索文本。

什么是"不同的搜索文本"？要具体！

你的问题似乎不是Java特有的。您当前的模式包含 (:|!) ，但没有一个示例表明输入中!如何发生。您可以使用p{Punct}来匹配名称和电子邮件周围的*，但除了 * 之外，您没有其他附件的示例。你没有说*的目的是什么;它们是外壳，通配符模式，什么？

以下模式似乎适用于某些目的：

(?:employee(Name|Email)):([w*@. ]+)