如果可能的话,我需要将下面的两个MySQL语句合并为一个ORACLE查询。
初始查询是
SELECT DISTINCT FIRST_NAME FROM PEOPLE WHERE LAST_NAME IN ("Smith","Jones","Gupta")
然后根据每个FIRST_NAME返回I查询
SELECT *
FROM PEOPLE
WHERE FIRST_NAME = {FIRST_NAME}
AND LAST_NAME IN ("Smith","Jones","Gupta")
ORDER BY FIELD(LAST_NAME, "Smith","Jones","Gupta") DESC
LIMIT 1
"List of last names"用作"default/override"指示符,因此每个名字只有一个人,如果存在多个相同名字的行,则只使用"last"列表中的last匹配。
我需要一个SQL查询,根据in (a,b,c)中值的顺序从"in"子句返回最后一行。下面是一个示例表,以及我需要从查询中得到的结果。
表PEOPLE,值
LAST_NAME FIRST_NAME
.....
Smith Mike
Smith Betty
Smith Jane
Jones Mike
Jones Sally
....
我需要一个基于DISTINCT FIRST_NAME和LAST_NAME IN ('Smith','Jones')的查询,返回
Betty Smith
Jane Smith
Mike Jones
Sally Jones
你可以这样做:
select first_name, last_name
from (
select p.first_name,
p.last_name,
row_number() over (partition by p.first_name
order by case p.last_name
when 'Smith' then 1
when 'Jones' then 2
when 'Gupta' then 3
end desc) as rn
from people p
where p.last_name in ('Smith','Jones','Gupta')
)
where rn = 1;
演示:SQL Fiddle
编辑
获取更多列并不难。我相信你再多花点功夫就能弄明白:
select *
from (
select p.*,
row_number() over (partition by p.first_name
order by case p.last_name
when 'Smith' then 1
when 'Jones' then 2
when 'Gupta' then 3
end desc) as rn
from people p
where p.last_name in ('Smith','Jones','Gupta')
)
where rn = 1;
或者这样:
select first_name,
max(last_name)
keep (dense_rank first order by decode(last_name,
'Smith', 1,
'Jones', 2,
'Gupta', 3) desc)
group by first_name
Oracle "FIRST"/"LAST"函数允许从最大/最小值行的其他列中获取值(例如获取员工的最大工资的last_name,或者像在这种情况下-从最大排名的行中获取last_name)
http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions056.htm