问题摘要
我正在尝试用复合键将多对一映射。到目前为止,我还没有找到另一个有帮助的问题。我知道如何使用一对一映射到复合键,但它不允许我将多个映射到一个。
下面您将看到bhrvJournalDAO有一个store_nbr列,该列映射到transAcctgBuTxtDAO acctg_bu_id。我如何点击复合键并告诉它只使用acctgBuId?我没有国家代码(这是复合密钥的第二部分(。
从此处
<hibernate-mapping>
<class name="com.acctg.BhrvJournalDAO" table="transpo_acctg:bhrv_journal">
<id name="jeId" column="je_id">
<generator class="native"/>
</id>
<property name="bhrvInvoiceId" column="bhrv_invoice_id"/>
<property name="storeNbr" column="store_nbr"/>
<property name="loadId" column="load_id"/>
<many-to-one name="transAcctgBuTxt" class="TransAcctgBuTxtDAO" insert="false" update="false" cascade="all">
<column name="store_nbr"></column>
</many-to-one>
</class>
到此
<hibernate-mapping>
<class name="TransAcctgBuTxtDAO" table="transpo_acctg:trans_acctg_bu_txt">
<composite-id name="transAcctgBuTxtPKDAO" class="TransAcctgBuTxtPKDAO">
<key-property name="acctgBuId" column="acctg_bu_id"/>
<key-property name="languageCode" column="language_code"/>
</composite-id>
<property name="acctgBuAbbr" type="java.lang.String">
<column name="acctg_bu_abbr" />
</property>
<property name="acctgBuDesc" type="java.lang.String">
<column name="acctg_bu_desc" />
</property>
<many-to-one name="transAcctgBuDAO" class="TransAcctgBuDAO" not-null="false"
insert="false" update="false" not-found="ignore" fetch="select">
<column name="acctg_bu_id" />
</many-to-one>
</class>
映射
<many-to-one name="transAcctgBuTxt" class="TransAcctgBuTxtDAO"
insert="false" update="false" cascade="all">
<column name="store_nbr"></column>
</many-to-one>
复合密钥示例
<one-to-one name="transAcctgBuTxt" class="TransAcctgBuTxtDAO" property-
ref="transAcctgBuTxtPKDAO.acctgBuId">
<column name = "store_nbr">
</one-to-one>
错误
Foreign key (FK47A121BB6617227C:transpo_acct:bhrv_journal [store_nbr]))
must have same number of columns as the referenced primary
key (transpo_acct:trans_acctg_bu_txt [acctg_bu_id,language_code])
提前感谢
由于TransAcctgBuTxtDAO具有2列的组合id,因此需要提供两个值来唯一标识一个实体,即句点。也许你可以重新考虑BhrvJournalDAO和TransAcctgBuTxtDAO之间是否真的是多对一的关系。也许它实际上是多对多的。