我有一个查询,我正在尝试另存为视图,但 SSMS 返回错误,指出有多个具有相同名称的列。
我试图将受影响的列重命名为别名,但没有成功。
每个视图或函数中的列名必须是唯一的。视图或函数"vwBlocks"中的列名"codemanQuestionID"被多次指定。
create view vwBlocks as
SELECT
LUConstructionType.codemanOptionID AS LUConstruction_codemanOptionID
, LUFascias.codemanOptionID AS LUFascias_codemanOptionID
, Block.windowsID
, LUWindows.windows
, LUWindows.codemanQuestionID AS codemanQuestion_ID
, Block.externalDoorID
, LUExternalDoor.externalDoor
, LUExternalDoor.codemanOptionID as LUExternal_codemanOptionID
FROM Block LEFT OUTER JOIN
LUOwnership ON Block.ownershipID = LUOwnership.ownershipID LEFT OUTER JOIN
LULocalAuthority ON Block.localAuthorityID = LULocalAuthority.authorityTypeID LEFT OUTER JOIN
LUConstructionType ON Block.constructionTypeID = LUConstructionType.constructionTypeID LEFT OUTER JOIN
LUTV ON Block.TVID = LUTV.TVID LEFT OUTER JOIN
LUSatellite ON Block.satelliteID = LUSatellite.satelliteID LEFT OUTER JOIN
LUPlayArea ON Block.playArea = LUPlayArea.playAreaID LEFT OUTER JOIN
LURoofCovering ON Block.roofCoveringID = LURoofCovering.roofCoveringID LEFT OUTER JOIN
LUFascias ON Block.fasciasID = LUFascias.fasciasID LEFT OUTER JOIN
LUWindows ON Block.windowsID = LUWindows.windowsID LEFT OUTER JOIN
LUExternalDoor ON Block.externalDoorID = LUExternalDoor.externalDoorID LEFT OUTER JOIN
LUcontractorInfo ON Block.contractorInfoID = LUcontractorInfo.contractorID LEFT OUTER JOIN
LUagentInfo ON Block.agentInfoID = LUagentInfo.agentID LEFT OUTER JOIN
LULandlord ON Block.LandlordID = LULandlord.landlordID LEFT OUTER JOIN
LUblockStatus ON Block.blockStatusID = LUblockStatus.blockStatusID LEFT OUTER JOIN
LUPropertyGroup ON Block.propertyGroup = LUPropertyGroup.propertyGroupID LEFT OUTER JOIN
LUCommunalBoilerType ON Block.communalBoilerType = LUCommunalBoilerType.communalBoilerID LEFT OUTER JOIN
LUExternalAreaManagedBy ON Block.externalAreaManagedBy = LUExternalAreaManagedBy.managedByID LEFT OUTER JOIN
LUgasBoilerMakeModel ON Block.CommBoilerMakeModelID = LUgasBoilerMakeModel.makeModelId LEFT OUTER JOIN
LUMaintenanceResp ON Block.maintenanceRepID = LUMaintenanceResp.maintenanceRepID
任何人都可以推荐解决方案吗?
提前感谢您的任何帮助。
我没有两次看到codemanQuestionID。这里有一些建议可以帮助我避免和/或解决此类问题。
至少有四种方法可以为列设置别名:
-
(表达式( AS ((别名((
( (别名(( = (表达式(
WITH ((cte name(( ((alias1(, (alias2(,...
FROM ((子查询(( AS ((别名 1>(,(别名 2,...
AS是最糟糕的IMO。它草率且令人困惑,尤其是当您不包括 AS 时。我通常使用的混叠样式是:
SELECT
col1 = <expression>,
col2 = <expression>,
colABC = <expression>
FROM schema.table1 AS t1
JOIN schema.table2 AS t2;
这使得调试工作变得更加容易。