c - 具有PIC12，MPLAB和UART的嵌入式应用程序没有输出

Question

我正在从事RGB LED项目，该项目由PIC12F1572控制。我正在使用的软件是带有HiTech C编译器的MPLAB IDE。计划是使用串行通信将LED RGB组合数据命令发送到PIC中，以存储在一个变量中，该变量将使其执行LED闪烁和发光，我已经能够建立UART通信。每个函数或步骤 I 代码的语法都是正确的，如果我编译，则可以在 linux 命令行终端上运行。如果我尝试在 MPLAB 中使用寄存器注入进行模拟，它会失败。我也想在模拟中运行它(有人知道寄存器注入在 MPLAB 中是如何工作的吗？当我尝试调试时我一起面临的问题。它可以编译但不起作用这是我的代码：关于该问题的任何想法或提示将不胜感激。我个人认为放置代码[分层方式]可能是错误的谢谢！

#include <xc.h>
#include "mcc.h"
#include "LED.h"
#include "tmr0.h"
#include "interrupt_manager.h"
void SetLedColor(uint16_t R_color, uint16_t G_color, uint16_t B_color);
void main(void)
{
    uint8_t data, i, j;
    uint16_t R_value, G_value, B_value;
    uint8_t value;
    uint8_t RX_Buffer[FRAMESIZE] ,RGB_data[6] ,HEX_data[6];
    // initialize the device
    SYSTEM_Initialize();
    INTERRUPT_GlobalInterruptEnable();           // Enable the Global Interrupts
    INTERRUPT_PeripheralInterruptEnable();   // Enable the Peripheral Interrupts
    while (1)
    {
        // EUSART_Write(0x61);
        while (!RCIF)
        {
            data = EUSART_Read();                     // Read received character
            for (i = 0; i < FRAMESIZE; i++)
            {
                RX_Buffer[i] = data;
            }
            EUSART_Write(data);
        }
        //check if any data is received
        for (j = 0; j = 5; j++)       // get the RGB value in the separate array
        {
            RGB_data[j] = RX_Buffer[j + 3];
            HEX_data[value] = RGB_data[j] / 16;
        }
        if (RX_Buffer[0] == 'R' && RX_Buffer[FRAMESIZE - 1] == 'n')
        {
            //ASCII to HEX separate values
            // uint32_t number = (uint32_t)strtol(HEX_data, NULL, 16);
            // R_value = number >>16;
            // G_value = (number & 0xffff) >> 8;
            // B_value = (number & 0x0000FF);
            R_value = (uint16_t) atoh(HEX_data[0], HEX_data[1]);
            G_value = (uint16_t) atoh(HEX_data[2], HEX_data[3]);
            B_value = (uint16_t) atoh(HEX_data[4], HEX_data[5]);
        }
        SetLedColor(R_value, G_value, B_value);
    }
}
void SetLedColor(uint16_t R_color, uint16_t G_color, uint16_t B_color)
{
    if (R_color == 0xFF)
    {
        LATAbits.LATA2 = 1;
    }
    else
    {
        LATAbits.LATA2 = 0;
    }
    if (G_color == 0xFF)
    {
        LATAbits.LATA4 = 1;
    }
    else
    {
        LATAbits.LATA4 = 0;
    }
    if (B_color == 0xFF)
    {
        LATAbits.LATA5 = 1;
    }
    else
    {
        LATAbits.LATA5 = 0;
    }
}

Answer 1

所以直到接收UART帧并回显回来，从存储数据使LED闪烁，我能够成功，这就是我想要的通过分层方式在这里的主要步骤。

#include "mcc_generated_files/mcc.h"
#include <stdlib.h>
#include <stdio.h>
#include "atoh.h"
#include "LED.h"
#define _XTAL_FREQ 16000000
#define FRAMESIZE 19
void main(void)
{
   uint8_t data,i,j,got_char;
   uint8_t R_value, G_value ,B_value;
   uint8_t value;
   uint8_t RX_Buffer[FRAMESIZE];
   uint8_t RGB_data[6] ,HEX_data[6];
    // initialize the device
    SYSTEM_Initialize();
    INTERRUPT_GlobalInterruptEnable();                       // Enable the Global Interrupts
    INTERRUPT_PeripheralInterruptEnable();                   // Enable the Peripheral Interrupts
  while (1)
 {
        if (EUSART_DataReady)
        {
            for (i = 0; i<FRAMESIZE; i++)
            {
                RX_Buffer[i] = EUSART_Read();
                if (RX_Buffer[i] == 'n')
                   break;
            }
            RX_Buffer[i] = 'n';                        //append 'n' at the end of stoaring array for detection of frame
            RX_Buffer[i+1] = '';                      // End of an array
            EUSART_WriteAnArrayOfBytes(RX_Buffer);

        if(RX_Buffer[0]=='R' && RX_Buffer[FRAMESIZE-2] == 'n')   //check for correct frame
          {
            LATAbits.LATA2 = 1;
            __delay_ms(2000);
            LATAbits.LATA2 = 0;
            __delay_ms(1000);
          }
        }
  }