如何在 GOLANG 中解组 JSON 并填充到结构中

Question

如何解组 json 并填充到结构中。就像我有销售订单和销售订单详细信息结构一样。在 json 中，我将有 1 条销售订单记录和多个项目用于销售订单详细信息结构。

这是我尝试过处理单个项目和多个项目的 go 代码，但仅适用于 salesorderdetails 结构的单个记录。

戈代码：

package main
import (
    "encoding/json"
    "fmt"
)
type Order struct {
    SalesId             string `json:"sales_id"`
    Customer string `json:"customer_name"`
    TotalPrice   string `json:"totalprice"`
}
type OrderDetails struct {
    DetailId             string `json:"detail_id"`
    SalesId             string `json:"sales_id"`
    ItemName string `json:"item_name"`
    Qty   string `json:"qty"`
    Price   string `json:"price"`
}
type Temp struct {
    Salesorder Order  `json:"Salesorder"`
    Salesorderdetails OrderDetails  `json:"OrderDetails"`
}
func main() {
    jsonByteArray := []byte(`[{"Salesorder":{"sales_id":"SOO1","customer_name":"CUST1","totalprice":"200"}, "OrderDetails":{"detailid":"1","sales_id":"SOO1","item_name":"ITEM1","qty":"2","price":"100"}}]`)
   //if i use above json it is working and if i use below json its not working
//jsonByteArray := []byte(`[{"Salesorder":{"sales_id":"SOO1","customer_name":"CUST1","totalprice":"200"}, "OrderDetails":{"detailid":"1","sales_id":"SOO1","item_name":"ITEM1","qty":"2","price":"100"},{"detailid":"2","sales_id":"SOO2","item_name":"ITEM2","qty":"3","price":"200"}}]`)
    var temp []Temp
    err := json.Unmarshal(jsonByteArray, &temp)
    if err != nil {
        panic(err)
    }
    fmt.Printf("%+vn", temp)
    fmt.Printf("%+vn ", temp[0].Salesorder.SalesId)
}

使用多个项目时出错：

panic: invalid character '{' looking for beginning of object key string

成功使用单个项目时的输出：

[{Salesorder:{SalesId:SOO1 Customer:CUST1 TotalPrice:200} Salesorderdetails:{SalesId:SOO1 ItemName:ITEM1 Qty:2 Price:100}}]
SOO1

小提琴：使用销售订单详细信息中的键进行更新

https://play.golang.org/p/klIAoNi18r

Answer 1

您要解码的内容不是有效的 JSON。 这将是有效的：

{
    "Salesorder": {
        "sales_id": "SOO1",
        "customer_name": "CUST1",
        "totalprice": "200"
    },
    "OrderDetails": {
        "sales_id": "SOO1",
        "item_name": "ITEM1",
        "qty": "2",
        "price": "100"
    }
}

但你给出的是：

{
    "Salesorder": {
        "sales_id": "SOO1",
        "customer_name": "CUST1",
        "totalprice": "200"
    },
    "OrderDetails": {
        "sales_id": "SOO1",
        "item_name": "ITEM1",
        "qty": "2",
        "price": "100"
    },
    {   // Things become invalid here
        "sales_id": "SOO2",
        "item_name": "ITEM2",
        "qty": "3",
        "price": "200"
    }
}

看起来您正在尝试提供对象列表，在这种情况下，您需要将这些对象包装在方括号中[]或者您必须为第二个OrderDetails对象提供自己的键。

Answer 2

试试这个：

package main
import (
    "encoding/json"
    "fmt"
)
type Order struct {
    SalesId     string `json:"sales_id"`
    Customer    string `json:"customer_name"`
    TotalPrice  string `json:"totalprice"`
}
type OrderDetails struct {
    SalesId   string `json:"sales_id"`
    ItemName  string `json:"item_name"`
    Qty       string `json:"qty"`
    Price     string `json:"price"`
}
type Temp struct {
    Salesorder Order                  `json:"Salesorder"`
    Salesorderdetails []OrderDetails  `json:"OrderDetails"`
}
func main() {
    jsonByteArray := []byte(`[{"Salesorder":{"sales_id":"SOO1","customer_name":"CUST1","totalprice":"200"}, "OrderDetails":[{"sales_id":"SOO1","item_name":"ITEM1","qty":"2","price":"100"},{"sales_id":"SOO2","item_name":"ITEM2","qty":"3","price":"200"}]}]`)
    var temp []Temp
    err := json.Unmarshal(jsonByteArray, &temp)
    if err != nil {
        panic(err)
    }
    //fmt.Printf("%+vn", temp)
    // Printing all Orders with some details
    for _, order := range temp {
        fmt.Println("Customer:", order.Salesorder.Customer)
        for _, details := range order.Salesorderdetails {
            fmt.Printf("    ItemName: %s, Price: %sn", details.ItemName, details.Price)
        }
    }
}

..订单详细信息现在是一个数组