如何从HBITMAP中获取一个特定的像素RGB值?我尝试在StackOverflow上阅读类似的帖子,但没有一个真正适合这个问题。下面的代码似乎在HBITMAP中获得了另一个位置(不是想要的位置)的RGB值。
int width = rc.right - rc.left;
int height = rc.bottom - rc.top;
HDC hdcSource = hdc; // the source device context
HBITMAP hSource = hbmp; // the bitmap selected into the device context
BITMAPINFO MyBMInfo = {0};
MyBMInfo.bmiHeader.biSize = sizeof(MyBMInfo.bmiHeader);
// Get the BITMAPINFO structure from the bitmap
if(0 == GetDIBits(hdcSource, hSource, 0, 0, NULL, &MyBMInfo, DIB_RGB_COLORS))
{
// error handling
}
// create the pixel buffer
BYTE* Pixels = new BYTE[MyBMInfo.bmiHeader.biSizeImage];
// We'll change the received BITMAPINFOHEADER to request the data in a
// 32 bit RGB format (and not upside-down) so that we can iterate over
// the pixels easily.
// requesting a 32 bit image means that no stride/padding will be necessary,
// although it always contains an (possibly unused) alpha channel
MyBMInfo.bmiHeader.biBitCount = 32;
MyBMInfo.bmiHeader.biCompression = BI_RGB; // no compression -> easier to use
// correct the bottom-up ordering of lines (abs is in cstdblib and stdlib.h)
MyBMInfo.bmiHeader.biHeight = abs(MyBMInfo.bmiHeader.biHeight);
// Call GetDIBits a second time, this time to (format and) store the actual
// bitmap data (the "pixels") in the buffer lpPixels
if(0 == GetDIBits(hdcSource, hSource, 0, MyBMInfo.bmiHeader.biHeight,
Pixels, &MyBMInfo, DIB_RGB_COLORS))
{
// error handling
}
int PixelX = 221;
int PixelY = 14;
cout << "R: " << (int)Pixels[4*((PixelX-1)+(PixelY-1)*width)] << " | G: " << (int)Pixels[4*((PixelX-1)+(PixelY-1)*width)+1] << " | B: " << (int)Pixels[4*((PixelX-1)+(PixelY-1)*width)+2] << endl;
编辑(使用用户1118321的解决方案)
height-1,因为 y 从 0 而不是 1 开始。
cout << "R: " << (int)Pixels[4*((PixelX)+(height-1-(PixelY))*width)] << " | G: " << (int)Pixels[4*((PixelX)+(height-1-(PixelY))*width)+1] << " | B: " << (int)Pixels[4*((PixelX)+(height-1-(PixelY))*width)+2] << endl;
Windows 位图从左下角开始存储其像素,Y 向上增加。尝试使用((height - 1) - PixelY)
而不仅仅是PixelY
,看看是否有帮助。